136 + 138+ 140
There is no set of three consecutive integers for 106.
Consecutive integers are ...-3,-2,-1,0,1,2,3...One right after the other.Two consecutive integers would be 5 and then one more, 6.
For any integer n, the numbers 2n + 1 and 2n + 3 are consecutive odd integers.
The integers are -6, -5 and -4 OR -7, -5 and -3 using only consecutive odd integers.
Divide the sum of the three consecutive integers by 3: 138/3 = 46. The smallest of these integers will be one less than 46 and the largest will be one more than 46, so the three consecutive integers will be 45, 46, and 47.
138 is, itself, an integer. It is impossible for any integer to lie between two consecutive integers.
The integers are 44, 46 and 48.
136 + 138+ 140
The simplest way is to solve 4n + 6 = 138 for the smallest of them.
Do-it-in-your-head method: The middle number MUST be a third of the total so 138 divided by 3 is 46, making your three numbers 44, 46 and 48. Shazam!
33, 34, 35, 36
There is no set of three consecutive integers for 106.
Start with "-3", then add one at a time to get as many consecutive integers as you want.
Divide the sum of the three consecutive odd integers by 3: -3 /3 = -1. The smallest of these integers will be two less than -1 and the largest will be two more than -1, so the three consecutive odd integers will be -3, -1, and +1.
201
Heading upwards from -3, the four consecutive integers are -3, -1, 1, 3.-3, -1, 1 and 3.