The simplest way is to solve 4n + 6 = 138 for the smallest of them.
The integers are 44, 46 and 48.
Do-it-in-your-head method: The middle number MUST be a third of the total so 138 divided by 3 is 46, making your three numbers 44, 46 and 48. Shazam!
The numbers are 45, 46 and 47.
The sets are 277, 279 and 136, 138, 140, 142.
The square root of 138 is approximately 11.747. So, the two consecutive whole numbers between which the square root of 138 lies are 11 and 12. This is because 11^2 is 121, which is less than 138, and 12^2 is 144, which is greater than 138.
33, 34, 35, 36
Divide the sum of the three consecutive integers by 3: 138/3 = 46. The smallest of these integers will be one less than 46 and the largest will be one more than 46, so the three consecutive integers will be 45, 46, and 47.
45, 46 and 47.
The integers are 44, 46 and 48.
136 + 138+ 140
Let the first lowest number be x, then x + x + 1 + x + 2 + x + 3 = 138 4x + 6 = 138 4x = 138 - 6 4x = 132 x = 33 and the number are 33, 34, 35, and 36, add them and you will get 138
Do-it-in-your-head method: The middle number MUST be a third of the total so 138 divided by 3 is 46, making your three numbers 44, 46 and 48. Shazam!
138 is, itself, an integer. It is impossible for any integer to lie between two consecutive integers.
I assume you mean what are the two consecutive integers. Algebraically; X = integers.X + (X + 1) = 2752X + 1 = 2752X = 274X = 137============solution setorSince the consecutive integers differ by 1, then the first number is 274/2 = 137, so the second one is 1 more, 138.
The numbers are 45, 46 and 47.
The three consecutive even numbers with a sum of 138 are 44, 46 and 48.
The equation to solve this is... x + (x + 2) + (x + 4) = 138 x + x + x + 2 + 4 = 138 3x + 6 = 138 3x = 132 x = 44 x = 44 x + 2 = 46 x + 4 = 48 So, the three consecutive even numbers that add up to 138 are... 44, 46, & 48