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Q: The sum of three consecutive even integers is 138 what are the integers?

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The integers are 44, 46 and 48.

The simplest way is to solve 4n + 6 = 138 for the smallest of them.

The numbers are 45, 46 and 47.

The sets are 277, 279 and 136, 138, 140, 142.

138 is an even number.Any numbers that end with; 0, 2, 4, 6, or 8 are considered an 'Even' number.

Related questions

136 + 138+ 140

The integers are 44, 46 and 48.

Divide the sum of the three consecutive integers by 3: 138/3 = 46. The smallest of these integers will be one less than 46 and the largest will be one more than 46, so the three consecutive integers will be 45, 46, and 47.

The three consecutive even numbers with a sum of 138 are 44, 46 and 48.

45, 46 and 47.

138 is, itself, an integer. It is impossible for any integer to lie between two consecutive integers.

The simplest way is to solve 4n + 6 = 138 for the smallest of them.

33, 34, 35, 36

The equation to solve this is... x + (x + 2) + (x + 4) = 138 x + x + x + 2 + 4 = 138 3x + 6 = 138 3x = 132 x = 44 x = 44 x + 2 = 46 x + 4 = 48 So, the three consecutive even numbers that add up to 138 are... 44, 46, & 48

The numbers are -48, -46 and -44 AND -47, -46, and -45. ( all negative numbers can be either odd or even)

I assume you mean what are the two consecutive integers. Algebraically; X = integers.X + (X + 1) = 2752X + 1 = 2752X = 274X = 137============solution setorSince the consecutive integers differ by 1, then the first number is 274/2 = 137, so the second one is 1 more, 138.

The numbers are 45, 46 and 47.

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