1) an insect trapped in amber
2) a mammoth frozen on the ground
3)petrified tree
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No. To check if a number is a multiple of 3 add its digits together and if this sum is a multiple of 3, then so is the original number. This sum can be continued until a single digit remains; if the single digit is 3, 6 or 9 then the original number is a multiple of 3, otherwise not. 19 → 1 + 9 = 10 10 → 1 + 0 = 1 which is not 3, 6 or 9, so 19 is not a multiple of 3.
No. To test: add the digits together and if the sum is divisible by 9, so is the original number. The test can be repeated on the sum until a single digit remains. If this single digit is 9 then the [original] number is divisible by 9, otherwise it gives the remainder when the [original] number is divided by 9. 534 → 5 + 3 + 4 = 12 12 → 1 + 2 = 3 3 ≠ 0 so 12 is not divisible by 9 so 534 is not divisible by 9; the remainder when 534 is divided by 9 is 3.
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Since the sum of the digits is divisible by 3, the original number is also divisible by 3.Since the sum of the digits is divisible by 3, the original number is also divisible by 3.Since the sum of the digits is divisible by 3, the original number is also divisible by 3.Since the sum of the digits is divisible by 3, the original number is also divisible by 3.
you can easely calculate it: the original measurements: 6(bottom)*6(height)*½=18 double the base half the height: 12*3*½=18 so it remains the same