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What equation is an expression of the rate of law?
r=[A]m[B]n APPLEX
What is the rate of a reaction if the value of k is 0.1 is 1 M and B is 2 M?
To calculate the rate of a reaction, you typically use the rate law equation, which can be expressed as ( \text{Rate} = k[A]^m[B]^n ), where ( k ) is the rate constant, ( [A] ) and ( [B] ) are the concentrations of the reactants, and ( m ) and ( n ) are their respective orders. Assuming a simple first-order reaction with respect to both A and B (i.e., ( m = n = 1 )), the rate would be calculated as ( \text{Rate} = 0.1 \times (1)^1 \times (2)^1 = 0.2 , \text{M/s} ). Thus, the reaction rate is 0.2 M/s.
What are th 4 fundamental laws in mathematics?
The Law of 4 Laws of addition and multiplication Commutative laws of addition and multiplication. Associative laws of addition and multiplication. Distributive law of multiplication over addition. Commutative law of addition: m + n = n + m . A sum isn't changed at rearrangement of its addends. Commutative law of multiplication: m · n = n · m . A product isn't changed at rearrangement of its factors. Associative law of addition: ( m + n ) + k = m + ( n + k ) = m + n + k . A sum doesn't depend on grouping of its addends. Associative law of multiplication: ( m · n ) · k = m · ( n · k ) = m · n · k . A product doesn't depend on grouping of its factors. Distributive law of multiplication over addition: ( m + n ) · k = m · k + n · k . This law expands the rules of operations with brackets (see the previous section).
What is k Rate kAmBn?
In the context of chemistry, "k Rate kAmBn" refers to the rate constant (k) of a reaction involving reactants A and B, where "m" and "n" represent the stoichiometric coefficients of these reactants in the rate law. The rate of the reaction can be expressed as proportional to the concentrations of A and B raised to their respective powers, leading to the equation: rate = k [A]^m [B]^n. This relationship helps in understanding how changes in concentration affect the speed of the reaction.
What are the different law of exponent?
Exponents are subject to many laws, just like other mathematical properties. These are X^1 = X, X^0 = 1, X^-1 = 1/X, X^m * X^n = X^m+n, X^m/X^n = X^m-n, (X^m)^n = X^(m*n), (XY)^n = X^n * Y^n, (X/Y)^n = X^n/Y^n, and X^-n = 1/X^n.
Which equation is an expression of the rate law?
Rate = k[A]m[B]n
What are m and n in the rate law equation rate kAmBn?
They are experimentally determined exponents.
What is an expression of the rate law?
r=[A]m[B]n APPLEX
What are m and n in the rate law equation?
They are experimentally determined exponents
What is the general form of a rate law?
The general form of a rate law is rate = k[A]^m[B]^n, where rate is the reaction rate, k is the rate constant, [A] and [B] are the concentrations of reactants A and B, and m and n are the respective reaction orders for A and B.
What equation shows how rate depends on concentrations of reactions?
The equation is called the rate law equation. For the reaction aA+bB =>cC+dD the rate law would be rate = k[A]^m[B]^n where k is the rate constant and m and n are the "order" with respect to each reactant. m and n must be determined experimentally and may or may not be the same as the coefficients a and b.
What equation is an expression of the rate of law?
r=[A]m[B]n APPLEX
What is the rate of a reaction that follows the rate law rate kAmBn if k 0.02 A and B are each 3 M m 2 and n 3?
The rate of the reaction can be calculated using the rate law rate = k[A]^m[B]^n. Plugging in the given values: rate = 0.02*(3)^3*(3)^3 = 0.022727 = 14.58 M/s.
Determine the rate of a reaction that follows the rate law rate kAmBn where k 0.2 A 3 M B 3 M m 1 n 2?
5.4 (apex)
What is the rate of a reaction that follows the rate law rate kAmBn where k 0.2 A3 M B3 M m1 n2?
The rate of the reaction can be calculated using the rate law equation rate = k[A]^m[B]^n. Plugging in the given values k = 0.2, m = 1, n = 2, [A] = 3 M, and [B] = 3 M into the equation gives rate = 0.2 * (3)^1 * (3)^2 = 16.2 M/s.
What is the rate constant of a reaction if rate 1 10 2 mol L s A is 2 M B is 3 M m 2 and n 1?
The rate law for this reaction is rate = k[A]^m[B]^n. From the given information, substituting the values for rate, [A], [B], and the exponents m and n, you can solve for the rate constant k. In this case, k = rate / ([A]^m[B]^n), so k = 2 / (10^2 * 3^1).
Determine the rate of a reaction that follows the rate law rate kAmBn where k 1.5 A 1 M B 3 M m 2 n 1?
4.5 (mol/L)/s
