11 plus 12 plus 13 can satisfy this
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1, 3, 5, 7, 9, 11 are six consecutive odd numbers whose sum is 36
Let's represent the four consecutive numbers as x, x+1, x+2, and x+3. The sum of these numbers is x + (x+1) + (x+2) + (x+3) = 4x + 6. We know that this sum equals 36, so we can set up the equation 4x + 6 = 36. Solving for x, we find x = 7. Therefore, the four consecutive numbers are 7, 8, 9, and 10.
36 / 3 = 13. So lets try 10, 12, 1410 +12+14 = 36
The numbers are 11, 12 and 13.
The numbers are 11, 12 and 13.