11 plus 12 plus 13 can satisfy this
1, 3, 5, 7, 9, 11 are six consecutive odd numbers whose sum is 36
The consecutive numbers that add up to 36 are 11, 12, and 13. When you add these three numbers together (11 + 12 + 13), the sum is 36.
Let's represent the four consecutive numbers as x, x+1, x+2, and x+3. The sum of these numbers is x + (x+1) + (x+2) + (x+3) = 4x + 6. We know that this sum equals 36, so we can set up the equation 4x + 6 = 36. Solving for x, we find x = 7. Therefore, the four consecutive numbers are 7, 8, 9, and 10.
36 / 3 = 13. So lets try 10, 12, 1410 +12+14 = 36
The numbers are 11, 12 and 13.
11+12+13=36
1, 3, 5, 7, 9, 11 are six consecutive odd numbers whose sum is 36
Assuming you mean how to solve what three consecutive numbers sum to some value: Divide the sum by three to get the middle number. The other two numbers are one less than this and one more than it. example: Which three consecutive numbers sum to 108? 108 ÷ 3 = 36 → The other two numbers are 36 - 1 = 35 and 36 + 1 = 37 → The three numbers are 35, 36, 37. 35 + 36 + 37 = 108 as required.
36
The consecutive numbers that add up to 36 are 11, 12, and 13. When you add these three numbers together (11 + 12 + 13), the sum is 36.
Let's represent the four consecutive numbers as x, x+1, x+2, and x+3. The sum of these numbers is x + (x+1) + (x+2) + (x+3) = 4x + 6. We know that this sum equals 36, so we can set up the equation 4x + 6 = 36. Solving for x, we find x = 7. Therefore, the four consecutive numbers are 7, 8, 9, and 10.
33, 36, 39, 42
36 / 3 = 13. So lets try 10, 12, 1410 +12+14 = 36
114
The numbers are 11, 12 and 13.
The numbers are 11, 12 and 13.
All the odd numbers.