depends if you are allowed to repeat a number or not. If you are it's 6 times 6 times 6 times 6 = 1296 If not then it's 6 times 5 times 4 times 3 = 360
16
A 4-digit number can range from 0000 to 9999, which includes all combinations of four digits. Since each digit can be any number from 0 to 9 (10 options), the total number of combinations is calculated as (10^4). Therefore, there are 10,000 different combinations for a 4-digit number.
The greatest 4-digit number that is divisible by 16 is 9984
To form a 3-digit odd positive integer using the digits 2, 3, 4, 5, and 6, the last digit must be an odd number. The available odd digits are 3 and 5. If we choose 3 as the last digit, we can use any of the remaining digits (2, 4, 5, 6) for the first two digits, giving us 4 options for the first digit and 4 options for the second digit (since we can repeat digits). This results in (4 \times 4 = 16) combinations. Similarly, if we choose 5 as the last digit, we again have 4 options for the first digit and 4 for the second, resulting in another (4 \times 4 = 16) combinations. Thus, the total number of odd 3-digit integers is (16 + 16 = 32).
There are 12C4 4 NUMBER combinations. And that equals 12*11*10*9/(4/3/2/1) = 495 combinations. However, some of these, although 4 number combinations consist of 7 digits eg 1, 10, 11, and 12. Are you really sure you want 4-DIGIT combinations?
This question needs clarificatioh. There are 4 one digit number combinations, 16 two digit combinations, ... 4 raised to the n power for n digit combinations.
16
A 4-digit number can range from 0000 to 9999, which includes all combinations of four digits. Since each digit can be any number from 0 to 9 (10 options), the total number of combinations is calculated as (10^4). Therefore, there are 10,000 different combinations for a 4-digit number.
The greatest 4-digit number that is divisible by 16 is 9984
To calculate the number of 4-digit combinations you can get from the numbers 1, 2, 2, and 6, we need to consider that the number 2 is repeated. Therefore, the total number of combinations is calculated using the formula for permutations of a multiset, which is 4! / (2!1!1!) = 12. So, there are 12 unique 4-digit combinations that can be formed from the numbers 1, 2, 2, and 6.
For the first digit you have 5 options, whichever you choose for the first digit, you have 4 options for the second digit, etc.; so the number of combinations is 5 x 4 x 3 x 2.For the first digit you have 5 options, whichever you choose for the first digit, you have 4 options for the second digit, etc.; so the number of combinations is 5 x 4 x 3 x 2.For the first digit you have 5 options, whichever you choose for the first digit, you have 4 options for the second digit, etc.; so the number of combinations is 5 x 4 x 3 x 2.For the first digit you have 5 options, whichever you choose for the first digit, you have 4 options for the second digit, etc.; so the number of combinations is 5 x 4 x 3 x 2.
To calculate the number of 4-number combinations possible with 16 numbers, you would use the formula for combinations, which is nCr = n! / r!(n-r)!. In this case, n = 16 (the total number of numbers) and r = 4 (the number of numbers in each combination). Plugging these values into the formula, you would calculate 16C4 = 16! / 4!(16-4)! = 1820. Therefore, there are 1820 possible 4-number combinations with 16 numbers.
To form a 3-digit odd positive integer using the digits 2, 3, 4, 5, and 6, the last digit must be an odd number. The available odd digits are 3 and 5. If we choose 3 as the last digit, we can use any of the remaining digits (2, 4, 5, 6) for the first two digits, giving us 4 options for the first digit and 4 options for the second digit (since we can repeat digits). This results in (4 \times 4 = 16) combinations. Similarly, if we choose 5 as the last digit, we again have 4 options for the first digit and 4 for the second, resulting in another (4 \times 4 = 16) combinations. Thus, the total number of odd 3-digit integers is (16 + 16 = 32).
There are 12C4 4 NUMBER combinations. And that equals 12*11*10*9/(4/3/2/1) = 495 combinations. However, some of these, although 4 number combinations consist of 7 digits eg 1, 10, 11, and 12. Are you really sure you want 4-DIGIT combinations?
To find the number of combinations of the digits 1, 2, 3, 4, 5, and 6 that form numbers less than 500, we can consider the constraints based on the first digit. If the first digit is 1, 2, or 3, all combinations of the remaining digits can be used. If the first digit is 4, only combinations that result in a two-digit number can be formed. The total combinations can be calculated based on these conditions, but generally, you can form various 1-digit, 2-digit, and 3-digit numbers, totaling around 120 distinct combinations.
the answer is = first 2-digit number by using 48= 28,82 and in 3 digit is=282,228,822,822
16. There are two choices for the first digit (3 and 6). For either choice of first digit there are two choices for the second digit, and so on. 2 x 2 x 2 x 2 = 16.