I'll do this for four cases (addition, subtraction, multiplication, and division) and values for n from 1 to 5. (value of n, final value)
Addition:
(1,7)
(2,10)
(3,13)
(4,16)
(5,19)
Subtraction:
(1,-1)
(2,2)
(3,5)
(4,8)
(5,11)
Multiplication:
(1,12)
(2,24)
(3,36)
(4,48)
(5,60)
Division:
(1,3/4)
(2,3/2)
(3,9/4)
(4,3)
(5,15,4)
They are 7, 10, 13, 16 and 19.
4, 6, 8, 10, 12
The formula (21n) represents a sequence where (n) is a positive integer. To find the first five terms, substitute (n) with values from 1 to 5: For (n = 1), the term is (21 \times 1 = 21). For (n = 2), the term is (21 \times 2 = 42). For (n = 3), the term is (21 \times 3 = 63). For (n = 4), the term is (21 \times 4 = 84). For (n = 5), the term is (21 \times 5 = 105). Thus, the first five terms are 21, 42, 63, 84, and 105.
The sum of the first five terms of a geometric series can be calculated using the formula ( S_n = a_1 \frac{1 - r^n}{1 - r} ), where ( a_1 ) is the first term, ( r ) is the common ratio, and ( n ) is the number of terms. Here, ( a_1 = 6 ), ( r = 13 ), and ( n = 5 ). Substituting these values into the formula gives: [ S_5 = 6 \frac{1 - 13^5}{1 - 13} = 6 \frac{1 - 371293}{-12} = 6 \cdot \frac{-371292}{-12} = 6 \cdot 30939 = 185634 ] Thus, the sum of the first five terms is 185634.
The simplest formula is: t(n) = 2n + 5 for n = 1, 2, 3, ... However, that is not the only formula; there are infinitely many polynomial formulae that can be found that give those five terms first, but for the 6th or further terms vary.
They are 7, 10, 13, 16 and 19.
4, 6, 8, 10, 12
They are 7, 10, 13, 16 and 19.
The formula (21n) represents a sequence where (n) is a positive integer. To find the first five terms, substitute (n) with values from 1 to 5: For (n = 1), the term is (21 \times 1 = 21). For (n = 2), the term is (21 \times 2 = 42). For (n = 3), the term is (21 \times 3 = 63). For (n = 4), the term is (21 \times 4 = 84). For (n = 5), the term is (21 \times 5 = 105). Thus, the first five terms are 21, 42, 63, 84, and 105.
A single number, such as 3461018, does not make a pattern.
All but John Adams served two terms. The total of the first five was nine terms or 36 years (almost - Washington's first term was about an month short.)
The simplest formula is: t(n) = 2n + 5 for n = 1, 2, 3, ... However, that is not the only formula; there are infinitely many polynomial formulae that can be found that give those five terms first, but for the 6th or further terms vary.
The sequence 4n + 7 represents a linear sequence where n is the position in the sequence. To find the first five terms, substitute n with 1, 2, 3, 4, and 5 respectively. Thus, the first five terms are 11, 15, 19, 23, and 27.
7
2,1,0 is th sequence of its terms
no clue
What does N equal? Well to solve the problem you would do N+7x1, N+7x2, N+7x 3, N+7x4, N+7x5 to figure out the first five terms.