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If: y = x+5 then y^2 = (x+5)^2

If: x^2 +4x +y^2 -18y +59 = 0 then x^2 +4x +(x+5)^2 -18(x+5) +59 = 0

Multiplying out brackets and collecting like terms: 2x^2 -4x -6 = 0

Dividing all terms by 2: x^2 -2x -3 = 0

Factorizing the above: (x+1)(x-3) = 0 meaning x = -1 or x = 3

Therefore by substitution points of intersection are at: (-1, 4) and (3, 8)

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Q: What are the points of intersection when the line y equals x plus 5 passes through the curve x2 plus 4x plus y2 -18y plus 59 equals 0?
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