If: y = x+5 then y^2 = (x+5)^2
If: x^2 +4x +y^2 -18y +59 = 0 then x^2 +4x +(x+5)^2 -18(x+5) +59 = 0
Multiplying out brackets and collecting like terms: 2x^2 -4x -6 = 0
Dividing all terms by 2: x^2 -2x -3 = 0
Factorizing the above: (x+1)(x-3) = 0 meaning x = -1 or x = 3
Therefore by substitution points of intersection are at: (-1, 4) and (3, 8)
The points of intersection are: (7/3, 1/3) and (3, 1)
Points of intersection work out as: (3, 4) and (-1, -2)
Where are the points!
The origin and infinitely many other points of the form (x, ax) where x is any real number.
In any triangle that is not equilateral, the Euler line is the straight line passing through the orthocentre, circumcentre and centroid. In an equilateral triangle these three points are coincident and so do not define a line.Orthocentre = point of intersection of altitudes.Circumcentre = point of intersection of perpendicular bisector of the sides.Centroid = point of intersection of medians.Euler proved the collinearity of the above three. However, there are several other important points that also lie on these lines. Amongst them,Nine-point Centre = centre of the circle that passes through the bottoms of the altitudes, midpoints of the sides and the points half-way between the orthocentre and the vertices.
The points of intersection are: (7/3, 1/3) and (3, 1)
Points of intersection work out as: (3, 4) and (-1, -2)
If: y = -8 -3x and y = -2 -4x -x^2 Then: -8 -3x = -2 -4x - x^2 Transposing terms: x^2 +x -6 = 0 Factorizing: (x-2)(x+3) = 0 => x = 2 or x = -3 Points of intersection by substitution are at: (2, -14) and (-3, 1)
Where are the points!
The points of intersection of the equations 4y^2 -3x^2 = 1 and x -2 = 1 are at (0, -1/2) and (-1, -1)
The slope of a line that passes through two points is (difference in y) / (difference in x).
The origin and infinitely many other points of the form (x, ax) where x is any real number.
It is a line that passes through or nearly passes through the plotted points on the coordinated grid.
In any triangle that is not equilateral, the Euler line is the straight line passing through the orthocentre, circumcentre and centroid. In an equilateral triangle these three points are coincident and so do not define a line.Orthocentre = point of intersection of altitudes.Circumcentre = point of intersection of perpendicular bisector of the sides.Centroid = point of intersection of medians.Euler proved the collinearity of the above three. However, there are several other important points that also lie on these lines. Amongst them,Nine-point Centre = centre of the circle that passes through the bottoms of the altitudes, midpoints of the sides and the points half-way between the orthocentre and the vertices.
y - 2 = 0
there are 6 lines can pass through 4 noncollinear points.
Write the equation of the line that passes through the points (3, -5) and (-4, -5)