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You gave a quadratic expression, not equation. Assuming you mean:
2x - 48 - x^2 = 0
Rearrange into standard form ax^2 + bx + c = 0:
-x^2 + 2x - 48 =0
You could directly apply the quadratic formula with a = -1, b = 2, c = -48; or you could multiply by -1 first, giving:
x^2 - 2x + 48 = 0
Then a = 1, b = -2, c = 48; it turns out that there are no real roots -- it has only complex roots, which are:
x = (1 + i√47) and (1 - i√47)
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The solutions of an equation are often called what?
The roots of the equation
What are quadratic equations with real roots?
If the discriminant of the quadratic equation is zero then it will have 2 equal roots. If the discriminant of the quadratic equation is greater than zero then it will have 2 different roots. If the discriminant of the quadratic equation is less than zero then it will have no roots.
What are the roots of a quadratic equation called?
Either "roots" or "solutions".
How is solving a quadratic equation the same as finding its roots?
That is what roots mean!
What roots of the quadratic equation are equivalent to xx-x-12 equals 0?
-4,3 are the roots of this equation, so for the values for which the sum of roots is 1 & product is -12
