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You gave a quadratic expression, not equation. Assuming you mean:

2x - 48 - x^2 = 0

Rearrange into standard form ax^2 + bx + c = 0:

-x^2 + 2x - 48 =0

You could directly apply the quadratic formula with a = -1, b = 2, c = -48; or you could multiply by -1 first, giving:

x^2 - 2x + 48 = 0

Then a = 1, b = -2, c = 48; it turns out that there are no real roots -- it has only complex roots, which are:

x = (1 + i√47) and (1 - i√47)

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Q: What are the roots when thequadratic equation 2x-48-x2?
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