0
Want this question answered?
Be notified when an answer is posted
Add your answer:
Earn +20 pts
What are the solutions for the quadratic equation 8x x2 - 9?
If you mean: x2+8x-9 = 0 then the solutions are x = 1 and x = -9
What are solutions to the equation x2-3x-4 equals 0?
They are x = -1 and x = 4.
How do you write a quadratic equation using only solutions 9 and 1?
Solutions: x = 9 and x = 1 Factored: (x-9(x-1) = 0 Equation: x2-10x+9 = 0
Why do equations of the form x2 equals k have no real solutoins when k0?
If the equation is x2 = k0 Then there are two solutions: + or - 1, since any number to 0 is 1 and 1 or -1 squared = 1.
When does a equation have two solutions?
Two cases in which this can typically happen (there are others as well) are: 1. The equation includes a square. Example: x2 = 25; the solutions are 5 and -5. 2. The equation includes an absolute value. Example: |x| = 10; the solutions are 10 and -10.
What are the solutions for the quadratic equation 8x x2 - 9?
If you mean: x2+8x-9 = 0 then the solutions are x = 1 and x = -9
What are solutions to the equation x2-3x-4 equals 0?
They are x = -1 and x = 4.
How do you write a quadratic equation using only solutions 9 and 1?
Solutions: x = 9 and x = 1 Factored: (x-9(x-1) = 0 Equation: x2-10x+9 = 0
Why do equations of the form x2 equals k have no real solutoins when k0?
If the equation is x2 = k0 Then there are two solutions: + or - 1, since any number to 0 is 1 and 1 or -1 squared = 1.
What is x2 -2x plus 2 equals 0?
It is a quadratic equation with no real roots or real solutions. In the complex domain, the solutions are 1 +/- i where i is the imaginary square root of -1.
When does a equation have two solutions?
Two cases in which this can typically happen (there are others as well) are: 1. The equation includes a square. Example: x2 = 25; the solutions are 5 and -5. 2. The equation includes an absolute value. Example: |x| = 10; the solutions are 10 and -10.
The Square of a number is 5 more than 4 times the number. Find the number that makes the sentence true.?
This is a quadratic equation which will have two solutions: X2 = 4x+5 Rearrange the equation: x2-4x-5 = 0 Factor the equation: (x+1)(x-5) = 0 So the solutions are: x = -1 or x = 5
What are the solutions to the equation x2 plus 4x-9 equals x plus 1?
x = 2 and x = -5
Does every quadratic equation have two distinct real numbers in its solution set?
Nope. Consider x2+0x+1=0. This means x2+1=0. This has two solutions, but they are complex numbers: +i and -i, where i is the squareroot of -1. How about x2+0x+0=0? This means x2=0. This has two solutions, sure, but they aren't distinct. In this case, x=0 for both solutions, so we just consider them one solution.
When you subtract one square number from another the answer is 16 what are the two squared numbers?
x2 -y2 =16 This is an equation that describes your problem. We can write this equation as (1/16)x2 -(1/16)y2 =1 You may recognize this as the equation whose graph is a hyperbola. So there are an infinite number of solutions.
What are the solutions for the simultaneous equation y plus 1 equals x and y equals x squared - 6x plus 5?
equation1: y+1 = x => y = x-1 equation 2: y = x2-6x++5 If, x2-6x+5 = x-1 then, x2-7x+6 = 0, solving this quadratic equation, x = 1 or x = 6 Substituting into equation 1: when x = 1, y = 0 and when x = 6, y = 5 Therefore the solutions are: x = 1, y = 0 and x = 6, y = 5
What is the discriminant for x2-4x-5 equals 0?
The discriminant is 36 which means the quadratic equation has two solutions which are 5 and -1
