Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "times", "equals", "squared", "cubed" etc. Please use "brackets" (or parentheses) because it is impossible to work out whether x plus y squared is x + y2 of (x + y) 2.
That's where x = 0. Replace x = 0, then solve for "y'.
If you mean: y = 4x-2 and y = x+13 then x = 5 and y = 18
To find the ordered pair for the expression ( y - x - 5 = yx + 1 ), we need to rearrange the equation. This can be rewritten as ( y - yx = x + 6 ) or ( y(1 - x) = x + 6 ). Solving for ( y ) gives ( y = \frac{x + 6}{1 - x} ). The ordered pair would depend on specific values of ( x ) and ( y ) that satisfy this equation. For example, if ( x = 0 ), then ( y = 6 ), yielding the ordered pair (0, 6).
yx * yx = y2x.Using the law of exponents, we add the 2 exponents, getting you 2x rather than just 'x'.
y=x^3
That's where x = 0. Replace x = 0, then solve for "y'.
If you mean: y = 4x-2 and y = x+13 then x = 5 and y = 18
The problem to solve is: xy+x+3y+3 Multiply y and x Multiply the y and x Multiply y and x The y just gets copied along. The x just gets copied along. The answer is yx yx x*y evaluates to yx x*y+x evaluates to yx+x Multiply y and 3 Multiply y and 1 The y just gets copied along. The answer is y y 3*y evaluates to 3y The answer is yx+x+3y x*y+x+3*y evaluates to yx+x+3y The answer is yx+x+3y+3 x*y+x+3*y+3 evaluates to yx+x+3y+3 ---- The final answer isyx+x+3y+3----
yx-3 is not an equation, and it has no graph.
x=y/7
x=y/7
What is the solution set for the equations x-y=2 and -x+y=2
yx * yx = y2x.Using the law of exponents, we add the 2 exponents, getting you 2x rather than just 'x'.
If y = 0 then yx - 5 = 0*x - 5 = 0 - 5 = -5
xy = x ÷x y = 1
y=x^3
It is simply: yx which in algebra means y times x