48/3 = 16 so the three numbers are 15, 16, 17
46+47+48=141
The three consecutive even numbers with a sum of 138 are 44, 46 and 48.
The numbers are 15, 16 and 17.
14, 16 & 18
The numbers are 47 and 48. (47 x 48 = 2,256)
46+47+48=141
The three consecutive even numbers with a sum of 138 are 44, 46 and 48.
Let the three numbers be 'n' , 'n+1', & n+2 ' . (consecutive). Summing n + n+1 + n+ 2 = 48 3n + 3 = 48 Subtract '3' from both sides 3n = 45 Divide both sides by '3'. n = 15 The smallest number. NB THe other two numbers are 15 + 1 = 16 & 15 + 2 = 17
The numbers are 15, 16 and 17.
The smallest is 14.
14, 16 & 18
The numbers are 47 and 48. (47 x 48 = 2,256)
x+ (x+1) + (x+2) = 48 3x+3 = 48 3x = 45 x = 15
They are: 48+50+52 = 150
You can either do this by trial-and error, or solve the equation n + (n + 2) + (n + 4) = 48.
The numbers are -18, -16 and -14.
The average of the three numbers is 50, so the other two must be 48 and 52.