46+47+48=141
The three consecutive even numbers with a sum of 138 are 44, 46 and 48.
The numbers are 15, 16 and 17.
14, 16 & 18
The numbers are 47 and 48. (47 x 48 = 2,256)
46+47+48=141
The three consecutive even numbers with a sum of 138 are 44, 46 and 48.
The smallest is 15.
The smallest is 14.
The numbers are 15, 16 and 17.
14, 16 & 18
The numbers are 47 and 48. (47 x 48 = 2,256)
x+ (x+1) + (x+2) = 48 3x+3 = 48 3x = 45 x = 15
They are: 48+50+52 = 150
You can either do this by trial-and error, or solve the equation n + (n + 2) + (n + 4) = 48.
The numbers are -18, -16 and -14.
The average of the three numbers is 50, so the other two must be 48 and 52.