The numbers are 15, 16 and 17.
They are: 48+50+52 = 150
48/3 = 16 so the three numbers are 15, 16, 17
The three consecutive even numbers with a sum of 138 are 44, 46 and 48.
48 + 49 = 97
14, 16 & 18
They are: 48+50+52 = 150
48/3 = 16 so the three numbers are 15, 16, 17
The three consecutive even numbers with a sum of 138 are 44, 46 and 48.
The smallest is 14.
48 + 49 = 97
14, 16 & 18
46+47+48=141
x+ (x+1) + (x+2) = 48 3x+3 = 48 3x = 45 x = 15
You can either do this by trial-and error, or solve the equation n + (n + 2) + (n + 4) = 48.
The numbers are -18, -16 and -14.
The average of the three numbers is 50, so the other two must be 48 and 52.
Three consecutive integers will always total a multiple of three. Specifically, they will always add up to three times the middle number. Divide 48 by 3. Choose the the integers on either side of that. 15 + 16 + 17 = 48 The three numbers could be described as x, x + 1 and x - 1. That adds up to 3x. 3x = 48 x = 16 x + 1 = 17 x - 1 = 15