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3p = 2p + 12subtracting 2p from both sidesp = 12 ■
8-3p-4 = 2p 4 - 3p = 2p add 3p to both sides 4 = 5p divide both sides by 5 4/5 = p
6p divide by 3p = 2
The expression can be simplified to: -8p--29
-2p+7.
3p = 2p + 12 subtract 2p from both sides 3p - 2p = 2p - 2p + 12 1p = 12 p = 12 this is how you solve this problem.
3p+7 = 16+2p 3p-2p = 16-7 p = 9
3p = 2p + 12subtracting 2p from both sidesp = 12 ■
6
6
8-3p-4 = 2p 4 - 3p = 2p add 3p to both sides 4 = 5p divide both sides by 5 4/5 = p
3p2-2p-5 = (3p-5)(p+1) when factored
6p divide by 3p = 2
4s 3p 3s 2p 1s This is probably one of the easiest chemistry problems in the book, you should probably look it up.
The electron configuration of CCl4 is 1s^2 2s^2 2p^6 3s^2 3p^2. This means that the carbon atom has 2 electrons in the 1s orbital, 2 electrons in the 2s orbital, 6 electrons in the 2p orbital, 2 electrons in the 3s orbital, and 2 electrons in the 3p orbital.
The expression can be simplified to: -8p--29
-5 + 3p - p = -5 + 2p