y - 2 = 4(x - 7)
If you mean a slope of -5 and a point of (6, 3) then the equation is y = -5x+33
If you mean a slope of 23 and a point of (0, 4) then the equation is y = 23x+4
To find the equation of the line with slope ( m = 8 ) that passes through the point ((-3, -6)), we can use the point-slope form of the equation of a line: ( y - y_1 = m(x - x_1) ). Substituting the values, we get: [ y + 6 = 8(x + 3). ] Simplifying this, the equation of the line is ( y = 8x + 18 ).
Slope 3 and point of (-1, 4)Equation: y-4 = 3(x--1) => y = 3x+7
Equation: y-3 = -5(x-6) => y = -5x+33
y = 4x - 26
Write the equation in slope-intercept form of the line that has a slope of 2 and contains the point (1, 1).
If you mean a slope of -5 and a point of (6, 3) then the equation is y = -5x+33
Slope: -5 Points: (6, 3) Equation: y = -5x+33
If you mean a slope of 23 and a point of (0, 4) then the equation is y = 23x+4
Slope: -3 Point: (4, -5) Equation: y = -3x+7
To find the equation of the line with slope ( m = 8 ) that passes through the point ((-3, -6)), we can use the point-slope form of the equation of a line: ( y - y_1 = m(x - x_1) ). Substituting the values, we get: [ y + 6 = 8(x + 3). ] Simplifying this, the equation of the line is ( y = 8x + 18 ).
Slope 3 and point of (-1, 4)Equation: y-4 = 3(x--1) => y = 3x+7
Point: (2, -1) Slope: -5 Equation: y = -5x+9
Equation: y-3 = -5(x-6) => y = -5x+33
Equation: y-3 = -5(x-6) => y = -5x+33
Equation: y-3 = -5(x-6) => y = -5x+33