5
Points: (-3, -2) and (1, 2) Slope: 1 Equation: y = x+1
The equation is: y-2 = 2(x-4) => y = 2x-2
slope-intercept from is y=mx+b, m is the slope and b is the y-intercept. put the values of the slope and y-intercept into the equation. y=2x-2
1) Solve the given equation for "y". The resulting equation will be in slope-intercept form, so you can immediately read off its slope. 2) Any line parallel to that line will have the same slope.
5
Point: (-6, -2) Slope: 5 Equation: y = 5x+28
Which of the following is the point-slope equation of the line with a slope equals -4 and a point of -2 3?
Coordinate: (1, 2) Slope: 4 Equation: y = 4x-2
y - 2x is not an equation. If that is supposed to be y = 2x then the slope is 2. Or, written as a slope, would be 2/1
Points: (-3, -2) and (1, 2) Slope: 1 Equation: y = x+1
The slope-intercept form of an equation is: y = mx + b Just copy down this equation, then replace "m" with the slope, and "b" with the y-intercept.
If you mean a slope of 4 and points of (0, 2) then the equation is y = 4x+2.
If the slope is 2 and the coordinate is (0, 3) then the equation is y = 2x+3
Write the equation in slope-intercept form of the line that has a slope of 2 and contains the point (1, 1).
The equation is: y-2 = 2(x-4) => y = 2x-2
If (p, q) is any point on the line, then the point slope equation is: (y - q)/(x - p) = 2 or (y - q) = 2*(x - p)