Q: What is the equation for the line that contains 1 2 and has a slope of 4?

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y = 2x - 1

Point: (2, -1) Slope: -5 Equation: y = -5x+9

Another point is needed to work out the slope and its straight line equation. Slope is worked out as: (y2-y1)/(x2-x1) ----------------------- With slope m and going through a point (x0, y0), a line has equation: y - y0 = m(x - x0) Thus the point-slope equation of a line with slope m through the point (-1, 2) is given by: y - 2 = m(x - -1) → y - 2 = m(x + 1)

Well. Slope intercept is y= mx + b. With B being the y intercept. If it contains 1,1 and the slope is positive 6, do the equation 1 = 6 (1) + b. 1 = 6 + b -5 = b. So the answer is y = 6x - 5

ok, here we go:The slope-intercept form is written as y = mx+b, where m is the slope and b is the y-intercept (the point where the line crosses the y-axis). It's usually easy to graph a line using y=mx+b.With this definition to figure out your equation we know:m=slope=3y=5x=2plug in all the #'s:5=3(2)+bb=-1your equation is:y=3x-1

Related questions

Write the equation in slope-intercept form of the line that has a slope of 2 and contains the point (1, 1).

y=2x+1

y = 2x - 1

The equation of the line will also depend on its slope which has not been given and so an answer is not possible.

The equation is (y - 1) = 2(x - 1) or, y = 2x - 1

The straight line equation for a line with a slope of 6 that goes through (1,2) works out as: y = 6x-4

Point: (2, -1) Slope: -5 Equation: y = -5x+9

Slope 3 and point of (-1, 4)Equation: y-4 = 3(x--1) => y = 3x+7

y=2x+1

Points: (1, 2) and (0, -2) Slope: 4 Equation: y = 4x-2

It works out as: y = 3x+8

The equation has no slope. The graph of the equation is a straight line with a slope of -1 .