The area of a sphere is A=4*3.14 * r^2. Thus the area varies as the square of the radius. If the surface area is increased by a factor of 4, then the radius will have to increase by the square root of 4 which is 2.
The surface area is reduced by a factor 4, the volume by a factor 8.
The area changes by the square of the same factor.
The surface area is quadrupled.
For areas: Square the Scale Factor.
The surface area will increase one hundred fold.
The area of a sphere is A=4*3.14 * r^2. Thus the area varies as the square of the radius. If the surface area is increased by a factor of 4, then the radius will have to increase by the square root of 4 which is 2.
No, if the radius of a sphere doubles, its surface area increases by a factor of 4, not simply doubling. The surface area of a sphere is proportional to the square of the radius.
The change in the area would increase by a factor of 4. When the diameter doubles, the radius also doubles. Since the formula for the surface area of a sphere is 4πr^2, when the radius doubles, the area increases by a factor of 4.
The surface area is reduced by a factor 4, the volume by a factor 8.
The area changes by the square of the same factor.
Nothing. The cylinder's surface area does not have a GCF.
It depends on the experiment!
The surface area increase by a factor of 49.
By a factor of 22 = 4.
As you would find the surface area of a normal shape using scale factors: to find the volume scale factor cubed, therefore to find the surface area of the hypercube, you do the scale factor to the power of four. geoffrz450@yahoo.co.uk
By a factor of 32 = 9. In general, surface area (for any two similar objects) is proportional to the square of any linear measurement.