A rectangle 10.5 x 3 will have a perimeter of 27 in.
Scale factor and perimeter are related because if the scale factor is 2, then the perimeter will be doubled. So whatever the scale factor is, that is how many times the perimeter will be enlarged.
44 x 1.5 = 66.
If you assume that 2.5 refers to the scale factor, you multiply each linear measurement by 2.5. This includes the width, the length, and - if you want to use it to construct your new rectangle - the diagonals. It also happens to include the perimeter, but you probably won't need that to construct the rectangle.
18" is not a possible perimeter measurement. Assume the dimensions of the rectangle are so close to those of a square that the difference can be disregarded. This is the condition when the perimeter is at its minimum. When the rectangle measures approximately 6" x 6", its area = 36 sq ins, its perimeter = 24" For the area to remain constant then as the length increases by a factor n the width must decrease by that same factor. Area = 6n x 6/n : perimeter = 12n + 12/n :so when n = 1, Perimeter = 12 + 12 = 24 As n increases, say n = 2, Perimeter = 24 + 6 = 30 : And the perimeter continues to increase as the rectangle becomes narrower. Eventually, it will become so narrow that for diagram purposes it will appear as a straight line.
A rectangle 10.5 x 3 will have a perimeter of 27 in.
if the length and breadth are increased by 5 times each area becomes 25 times
uhhum i domt know
Scale factor and perimeter are related because if the scale factor is 2, then the perimeter will be doubled. So whatever the scale factor is, that is how many times the perimeter will be enlarged.
44 x 1.5 = 66.
(20,5)
If you assume that 2.5 refers to the scale factor, you multiply each linear measurement by 2.5. This includes the width, the length, and - if you want to use it to construct your new rectangle - the diagonals. It also happens to include the perimeter, but you probably won't need that to construct the rectangle.
It depends on the aspect ratio. If it is a square object then it should scale up evenly. But if it is a rectangle then eventually a large enough scale factor will make it looked stretch on the longer sides.
The ratio of the perimeters is equal to the scale factor. If rectangle #1 has sides L and W, then the perimeter is 2*L1 + 2*W1 = 2*(L1 + W1).If rectangle # 2 is similar to #1 and sides are scaled by a factor S, so that L2 = S*L1 and W2 = S*W1, the perimeter of rectangle #2 is 2*(L2 + W2)= 2*(S*L1 + S*W1) = S*2*(L1 + W1) = S*(perimeter of rectangle #1).
If the side lengths of a rectangle are halved, the perimeter of the rectangle would also be halved. This is because the perimeter of a rectangle is calculated by adding the lengths of all four sides. If each side length is halved, then the total length around the rectangle would also be halved.
Absolutely nothing. A scale factor of 1 is the same as saying do not change the scale.
18" is not a possible perimeter measurement. Assume the dimensions of the rectangle are so close to those of a square that the difference can be disregarded. This is the condition when the perimeter is at its minimum. When the rectangle measures approximately 6" x 6", its area = 36 sq ins, its perimeter = 24" For the area to remain constant then as the length increases by a factor n the width must decrease by that same factor. Area = 6n x 6/n : perimeter = 12n + 12/n :so when n = 1, Perimeter = 12 + 12 = 24 As n increases, say n = 2, Perimeter = 24 + 6 = 30 : And the perimeter continues to increase as the rectangle becomes narrower. Eventually, it will become so narrow that for diagram purposes it will appear as a straight line.