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What if any are the points of intersection of the parabolas of y equals x2 -4x plus 8 and y equals 8x -x2 -14?
Wiki User
∙ 7y ago
If: y = x^2 -4x +8 and y = 8x -x^2 -14
Then: x^2 -4x+8 = 8x -x^2 -14
Transposing terms: 2x^2 -12x+22 = 0
Divide all terms by 2: x^2 -6x +11 = 0
Using the discriminant b^2 -4(ac): 36 -4(1*11) = -8
Therefore it follows that there are no points of intersection because the discriminant is less than zero.
Wiki User
∙ 7y ago
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What is the point of intersection of the parabolas of y equals 3x squared plus 10x plus 11 and y equals 2 -2x -x squared?
They intersect at the point of: (-3/2, 11/4)
What are the coordinates for x2 plus y2 equals 185 and x plus y equals 17?
We believe that those equations have no real solutions, and that their graphs therefore have no points of intersection.
What are the points of intersection of y equals x squared plus 2x plus 2 with y equals x cubed plus 2?
x2-x3+2x = 0 x(-x2+x+2) = 0 x(-x+2)(x+1) = 0 Points of intersection are: (0, 2), (2,10) and (-1, 1)
What are the points of intersection of the parabolas y equals 4x squared -2x -1 and -2x squared plus 3x plus 5 showing key stages of work?
If: y = 4x2-2x-1 and y = -2x2+3x+5 Then: 4x2-2x-1 = -2x2+3x+5 So: 6x2-5x-6 = 0 Solving the quadratic equation: x = -2/3 or x = 3/2 Points of intersection by substitution: (-2/3, 19/9) and (3/2, 5)
What are the points of intersection of the parabolas when y equals -2x squared plus 3x plus 5 and y equals 4x squared -2x -1 showing work?
If: y = -2x^2 +3x +5 and y = 4x^2 -2x -1 Then: 4x^2 -2x -1 = -2x^2 +3x +5 So it follows: 6x^2 -5x -6 = 0 Using the quadratic equation formula: x = -2/3 or x = 3/2 Therefore points of intersection by substitution are at: (-2/3, 19/9) and (3/2, 5)
What is the point of intersection of the parabolas of y equals 3x squared plus 10x plus 11 and y equals 2 -2x -x squared?
They intersect at the point of: (-3/2, 11/4)
What are the points of intersection of the parabolas of y equals 4x squared -12x -3 and y equals x squared plus 11x plus 5 on the Cartesian plane?
The points are (-1/3, 5/3) and (8, 3).Another Answer:-The x coordinates work out as -1/3 and 8Substituting the x values into the equations the points are at (-1/3, 13/9) and (8, 157)
What is the point of intersection of the parabolas y equals x2 plus 20x plus 100 and y equals x2 -20x plus 100 showing work?
If: y = x2+20x+100 and x2-20x+100 Then: x2+20x+100 = x2-20x+100 So: 40x = 0 => x = 0 When x = 0 then y = 100 Therefore point of intersection: (0, 100)
What are the coordinates for x2 plus y2 equals 185 and x plus y equals 17?
We believe that those equations have no real solutions, and that their graphs therefore have no points of intersection.
What is if any are the points of intersection of the parabolas y equals x2 -4x plus 8 and y equals 8x -x2 -14 showing work with explanations?
If: y = x2-4x+8 and y = 8x-x2-14 Then: x2-4x+8 = 8x-x2-14 So: 2x2-12x+22 = 0 Discriminant: 122-(4*2*22) = -32 Because the discriminant is less than 0 there is no actual contact between the given parabolas
What are the points of intersection of y equals x squared plus 2x plus 2 with y equals x cubed plus 2?
x2-x3+2x = 0 x(-x2+x+2) = 0 x(-x+2)(x+1) = 0 Points of intersection are: (0, 2), (2,10) and (-1, 1)
What are the points of intersection of the parabolas y equals 4x squared -2x -1 and -2x squared plus 3x plus 5 showing key stages of work?
If: y = 4x2-2x-1 and y = -2x2+3x+5 Then: 4x2-2x-1 = -2x2+3x+5 So: 6x2-5x-6 = 0 Solving the quadratic equation: x = -2/3 or x = 3/2 Points of intersection by substitution: (-2/3, 19/9) and (3/2, 5)
What are the points of intersection of the parabolas when y equals -2x squared plus 3x plus 5 and y equals 4x squared -2x -1 showing work?
If: y = -2x^2 +3x +5 and y = 4x^2 -2x -1 Then: 4x^2 -2x -1 = -2x^2 +3x +5 So it follows: 6x^2 -5x -6 = 0 Using the quadratic equation formula: x = -2/3 or x = 3/2 Therefore points of intersection by substitution are at: (-2/3, 19/9) and (3/2, 5)
What are the points of intersection of the parabolas y equals 4x squared -2x -1 and y equals -2x squared plus 3x plus 5 showing work with answers?
If: y = 4x^2 -2x -1 and y = -2x^2 +3x +5 Then: 4x^2-2x-1 = -2x^2+3x+5 =>6x^2-5x-6 = 0 Solving the above quadratic equation: x = -2/3 or x = 3/2 Therefore by substitution the points of intersection are: (-2/3, 19/9) and (3/2, 5)
What are the points of intersection of the parabolas y equals 4x squared -2x -1 and y equals -2x squared plus 3x plus 5 showing work and answers?
If: y = 4x^2 -2x -1 and y = -2x^2+3x+5 Then: 4x^2 -2x -1 = -2x^2+3x+5 => 6x^2-5x-6 = 0 Solving the above quadratic equation: x = -2/3 or x = 3/2 Therefore the points of intersection by substitution are: (-2/3, 19/9) and (3/2, 5)
What are the points of intersection of the parabolas y equals x squared -2x plus 4 and y equals 2x squared -4x plus 4?
If: y = x^2 -2x +4 and y = 2x^2 -4x +4 Then: 2x^2 -4x +4 = x^2 -2x +4 Transposing terms: x^2 -2x = 0 Factorizing: (x-2)(x+0) => x = 2 or x = 0 Therefore by substitution points of intersect are at: (2, 4) and (0, 4)
Where are the points of intersection of the parabolas y equals plus 4x squared -2x -1 and y equals -2x squared plus 3x plus 5 on the Cartesian plane showing details of work?
If: y = 4x2-2x-1 and y = -2x2+3x+5 Then: 4x2-2x-1 = -2x2+3x+5 And so: 6x2-5x-6 = 0 Using the the quadratic equation formula: x = -2/3 and x = 3/2 Substitution: when x = -2/3 then y = 19/9 and when x = 3/2 then y = 5 Points of intersection: (-2/3, 19/9) and (3/2, 5)
