x5+4x4-6x2+nx+2 when divided by x+2 has a remainder of 6 Using the remainder theorem: n = 2
(3x - 5x) + (x2 - 6x2) = -2x -5x2 = -x(2 + 5x)
6x2-24=0 6(x2-4)=0 x= {-2,2}
5x + 10 = 5(x+2) 6x2 + 12x = 6x(x+2) The only common factor is x+2
(6 × 2) + 3 = 15
(-6*2)/-3-12/-34
7 + 24 ÷ (6x2) =7 + 24 ÷ 12 = 7 + 2 = 9
x5+4x4-6x2+nx+2 when divided by x+2 has a remainder of 6 Using the remainder theorem: n = 2
The polynomial 7x3 + 6x2 - 2 has a degree of 3, making it cubic.
= -10
2(3x2 - 2)
6x2-18x+12 = (6x-6)(x-2)
246x^2
6x2 + 14x -12 = (3x - 2) (2x + 6). There they are.
Area 36x4-64x2 and width is 6x2-8x Area = Length * width36x4 -64x2 = L * 6x2 -8x(36x4 -64x2) / (6x2 -8x) = L(36x4 -64x2) / (6x2 -8x) = L((6x2 -8x)2 + 96x3)/ (6x2 -8x) = L1 + 96x3/ (6x2 -8x) = L1 + 96x3/ x(6x -8) = L1 + 96x2/ (6x -8) = L
(3x - 5x) + (x2 - 6x2) = -2x -5x2 = -x(2 + 5x)
If: 6x2+11x-10 = 0 Then: x = -5/2 and x = 2/3