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What is m 2?
5(m-2) - m(m-2)
What are the factors of the quadratic function -m2 3m-2?
-m2+3m-2 -m2+2m+m-2 -m(m -2)+1(m-2) (-m+1)(m-2) or
7m(m-2) plus 6n(2-m)?
factor by grouping 7m(m-2)+6n(2-m)
What is the total if I Subtract 2 from m?
m-2
How do you factor using two m squared minus eight?
2m^2 - 8 = 2(m^2 - 4) = 2(m-2)(m+2). A difference of squares, x^2 - y^2 say (or m^2 - 2^2 above), factorises as (x - y)(x + y).
What is m-2 over m plus 2 times m over m-1?
(m-2)/(m+2) * m/(m-1) = [(m-2)*m]/[(m+2)*(m-1)] = (m2 - 2m)/m2 + m - 2)
What is 5(m-2) - m(m-2)?
5(m-2) - m(m-2)
What is is 2 m?
5(m-2) - m(m-2)
What is m 2?
5(m-2) - m(m-2)
What is the answer to m plus m when equals 2?
m+m when m equals 2. 2+2 4
What is 'm2-m-3 times m-4?
( m^2 - m - 3 ) + ( m - 4 ) = m^2 - m - 3 + m - 4 = m^2 - 7Answer: m^2 - 7
What are the factors of the quadratic function -m2 3m-2?
-m2+3m-2 -m2+2m+m-2 -m(m -2)+1(m-2) (-m+1)(m-2) or
If m plus 9 equals 2 what is m?
m + 9 = 2 Therefore, m = 2 - 9 m = -7
7m(m-2) plus 6n(2-m)?
factor by grouping 7m(m-2)+6n(2-m)
The sum of the squares of two consecutive positive numbers is 85?
Let the numbers be m & m+1 (consecutive) Hence their squares are m^2 & ( m + 1)^2 => m^2 & m^2 + 2m + 2 Hence Their sum is m^2 + m^2 + 2m + 1 = 85 2m^2 + 2m - 84 = 0 m^2 + m - 42 =0 Factor (m + 7)(m - 6) = 0 Hence the numbers are 6 & 7 .
Find two consecutive positive even numbers the sum of whose squares is 340?
Let the number be 'm' & 'm + 2' Hence their squares are m^2 & (m+2)^2 There sum is m^2 + (m+2)^2 = 340 Multiply out he brackets m^2 + m^2 + 4m + 4 = 340 . 2m^2 + 4m + 4 = 340 Divide both sides by '2' m^2 + 2m + 2 = 170 m^2 + 2m - 168 = 0 Factor (m - 12)(m + 14) = 0 Hence m = 12 & m+ 2 = 14 The two consecutive even numbers. 12^2 = 144 14^2 = 196 144 + 196 = 340 As required.
What is the answer to m2-8m equals -16?
if by m2 you mean m multiplied by 2, then m= 2 2/3if by m2 you mean m squared, then m still =2 2/3, because the m squared becomes m times m which equals 2m
