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What equations are equivalent to 3p(p plus 2)?
None because without an equality sign it is not an equation but it can be simplified to 3p^2 +6p
What is the perpendicular bisector equation of the line joined by the points of p q and 7p 3q on the Cartesian plane?
Points: (p, q) and (7p, 3q) Midpoint: (4p, 2q) Slope: q/3p Perpendicular slope: -3p/q Perpendicular bisector equation:- => y-2q = -3p/q(x-4p) => qy-2q^2 = -3p(x-4p) => qy-2q^2 = -3px+12p^2 => qy = -3px+12p^2+2q^2 In its general form: 3px+qy-12p^2-2q^2 = 0
What is the answer to -3p-5 - 7p plus 2p-18 - 6?
The expression can be simplified to: -8p--29
What expression is equal to p 3p 4 - 2p?
The expression (3p^4 - 2p) cannot be simplified further without knowing specific values for (p). However, it can be factored as (p(3p^3 - 2)), which highlights (p) as a common factor.
What is the perpendicular bisector equation of the line segment of p q and 7p 3q?
In its general form it works out as: 3px+qy-12p2-2q2 = 0Improved Answer:-Points:(p, q) and (7p, 3q)Slope: q/3pPerpendicular slope: -3p/qMidpoint: (4p, 2q)Equation: y-2q = -3p/q(x-4p) => yq = -3px+12p2+2q2Perpendicular bisector equation in its general form: 3px+qy-12x2-2q2 = 0
What is 3p-2-29?
They are three terms of an expression that can be simplified to: 3p -31
What is -2(-3)(-4) simplified?
They are three terms of an expression that can be simplified to: 3p -31
What is p plus q and 2p?
Oh, dude, it's like this: if you have p plus q, you just add the two together. And then, if you have 2p, you're basically doubling p. So, technically, the answer is p + q and 2p. Hope that clears things up for ya!
What equations are equivalent to 3p(p plus 2)?
None because without an equality sign it is not an equation but it can be simplified to 3p^2 +6p
What is 12p plus 19q plus p - 5q - 3p?
To simplify the expression 12p + 19q + p - 5q - 3p, we first combine like terms. Combining the p terms, we have 12p + p - 3p, which simplifies to 10p. Combining the q terms, we have 19q - 5q, which simplifies to 14q. Therefore, the simplified expression is 10p + 14q.
Find 2p2 plus 3p - 4 less - 2p2 - 3p plus 4.?
This expression when simplified comes to: 0
How do you solve 1.50p plus 2.50p plus 3p This is a simplifying algebraic expressions and add subtract integer problem?
It is: 1.50p+2.50p+3p = 7p when simplified
What is the perpendicular bisector equation of the line joined by the points of p q and 7p 3q on the Cartesian plane?
Points: (p, q) and (7p, 3q) Midpoint: (4p, 2q) Slope: q/3p Perpendicular slope: -3p/q Perpendicular bisector equation:- => y-2q = -3p/q(x-4p) => qy-2q^2 = -3p(x-4p) => qy-2q^2 = -3px+12p^2 => qy = -3px+12p^2+2q^2 In its general form: 3px+qy-12p^2-2q^2 = 0
What is the sum of the quotient of p and 14 and the quotient of q and 3?
p/14 + q/3 = (3p + 14q)/ 42
What is the answer to -3p-5 - 7p plus 2p-18 - 6?
The expression can be simplified to: -8p--29
What is 3p-pq 2pr factorized?
3p-pq 2pr factorized = 1
How do you form an equation for the perpendicular bisector of the line segment joining the points of p q and 7p 3q showing all details of your work?
First find the midpoint the slope and the perpendicular slope of the points of (p, q) and (7p, 3q) Midpoint = (7p+p)/2 and (3q+q)/2 = (4p, 2q) Slope = (3q-q)/(7p-p) = 2q/6p = q/3p Slope of the perpendicular is the negative reciprocal of q/3p which is -3p/q From the above information form an equation for the perpendicular bisector using the straight line formula of y-y1 = m(x-x1) y-2q = -3p/q(x-4p) y-2q = -3px/q+12p2/q y = -3px/q+12p2/q+2q Multiply all terms by q and the perpendicular bisector equation can then be expressed in the form of:- 3px+qy-12p2-2q2 = 0
