3x = x + 4 x = 2 3x2=6 2+4=6
(3x-4)(x+5)
3x2 - 11x - 4 = 0(3x + 1)(x - 4)x = -1/3 and 4
3x2 = 21 describes two single values, and does not have an x intercept. 3x2 = 21 ∴ x2 = 7 ∴ x = ±√7
3x2 + 10x - 8 = 0 3x2 + 12x - 2x - 8 = 0 3x(x + 4) - 2(x + 4) = 0 (3x - 2)(x + 4) = 0 So 3x - 2 = 0 or x + 4 = 0 so x = 2/3 or x = -4
3x2+x-4 = 0 (3x+4)(x-1) = 0 Solutions: x = 1 and x = -4/3 By using the quadratic equation formula.
3x2 - 10x - 8 = (3x + 2) (x - 4)
3x = x + 4 x = 2 3x2=6 2+4=6
I guess that should be 3 times (x squared) minus 48: 3x2 - 48 = 3(x2 - 16) = 3(x + 4)(x - 4)
If you mean 3x2-7x+x = -4 then there are no solutions because the discriminant of the quadratic equation is less than zero.
(3x-4)(x+5)
3x2+14x+8 = 0 x = -2/3 or x = -4
3x2 - 11x - 4 = 0(3x + 1)(x - 4)x = -1/3 and 4
Set the equation equal to zero. 3x2 - x = -1 3x2 - x + 1 = 0 The equation is quadratic, but can not be factored. Use the quadratic equation.
(3x + 2)(x + 2) so x = -2/3 or -2
3x2 = 21 describes two single values, and does not have an x intercept. 3x2 = 21 ∴ x2 = 7 ∴ x = ±√7
3x2 + 10x - 8 = 0 3x2 + 12x - 2x - 8 = 0 3x(x + 4) - 2(x + 4) = 0 (3x - 2)(x + 4) = 0 So 3x - 2 = 0 or x + 4 = 0 so x = 2/3 or x = -4