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This is impossible as the variables are different
6x3 + 9x2 - 2x2 - 3x Before any grouping, take out the common factor, x, to give x*(6x2 + 9x - 2x - 3) = x*[3x*(2x + 3) - 1*(2x + 3)] = x*(2x + 3)*(3x - 1)
5x3 - 3x2 + 2x = x*(5x2 - 3x + 2) The quadratic has no real factors.
3x2-2x-8 = (3x+4)(x-2) when factored
3x(2x + 1)