This is impossible as the variables are different
6x3 + 9x2 - 2x2 - 3x Before any grouping, take out the common factor, x, to give x*(6x2 + 9x - 2x - 3) = x*[3x*(2x + 3) - 1*(2x + 3)] = x*(2x + 3)*(3x - 1)
5x3 - 3x2 + 2x = x*(5x2 - 3x + 2) The quadratic has no real factors.
3x2-2x-8 = (3x+4)(x-2) when factored
3x(2x + 1)
This is impossible as the variables are different
6x3 + 9x2 - 2x2 - 3x Before any grouping, take out the common factor, x, to give x*(6x2 + 9x - 2x - 3) = x*[3x*(2x + 3) - 1*(2x + 3)] = x*(2x + 3)*(3x - 1)
3x squared - x squared = 2x squared
5x3 - 3x2 + 2x = x*(5x2 - 3x + 2) The quadratic has no real factors.
2x squared - 3x
x(3x - 2)
2x2 x 3x2 = 6 x4 (2x)2 x (3x)2 = 36 x4
5
Since you add up the 'x''s (i.e. (2x) (3x) (4x) = 24x cubed) 6x2
6x2 + 10x = 2x*(3x + 5)
3x2-2x-8 = (3x+4)(x-2) when factored
If the equation is (2x)^3-3x, then the answer is -985. However, if the equation if 2(x)^3-3x, then the answer is -235.