3x2 -4 (x=3)
3(32)-4
3(9)-4
27-4=23
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3x^2+3x-60=3(x^2+x+20)=3(x+5)(x-4)
It is: (3x+4)(2x-3) when factored
(x+4)(x-7)
Your factors must begin 3x and x to give 3x2. The factors of 12 are 1/12, 2/6 and 3/4. Which pair, together with 3x and x, can add to -5? 3 and 4 seem to fit the bill: (3x + 4)(x - 3)
3x2 - 11x - 4 = 0(3x + 1)(x - 4)x = -1/3 and 4