5 - 3y
As an algebraic expression it is: 3y-5
3y+5=y-3 subtract the y from the other side then: 2y+5=-3 subtract the 5 2y=-8 then divide 2 by both sides and your final answer should be: y= - 4
y² - y - 6 = (y + 2)(y - 3)
It is a quadratic equation in the form of y2-4y-5 = 0 and will have two solutions: When factorised: (y-5)(y+1) = 0 Therefore: y = 5 or y = -1
5 - 3y
As an algebraic expression it is: 3y-5
if your question says 5(y+3) or 5 * (y+3) then its 5y+15
No. The subtraction operator is a binary operator that returns the result of subtracting the rhs operand from the lhs operand. The unary minus operator simply negates the rhs operand. int x = -5; // unary minus. x is (-5) int y = -x; // unary minus. y is (+5) y -= x; // binary minus/assign operator. y is (+10) --x; // unary decrement operator. x is (-6) y -= (-x); // binary minus/assign and unary minus operators. y is(+4)
3y+5=y-3 subtract the y from the other side then: 2y+5=-3 subtract the 5 2y=-8 then divide 2 by both sides and your final answer should be: y= - 4
y² - y - 6 = (y + 2)(y - 3)
He has to1) subtract MINUS 7 for y'2) Use MINUS 3 and MINUS 5 for x and x'He incorrectly wrote this(y - y') / (x - x')like this:(10 - 7) / 3 + 5)He should have written this:(10 - (-7)) / (-3 -5)This comes out to(10 + 7) / (- 3 -5)17 / - 8Correct answer:Slope = 17 / - 8
y - 3
y(y-3)(y+3)
It is a quadratic equation in the form of y2-4y-5 = 0 and will have two solutions: When factorised: (y-5)(y+1) = 0 Therefore: y = 5 or y = -1
it depends,if y = 0 the answer is -12 if y = 5 then the answer is 368
Locate the turning point(s) for the following functions. (a) y=x3-x2 -3x + 5 3