As an algebraic expression it is: 3y-5
The expression for 5 minus the product of ( y ) and 3 can be written as ( 5 - (3y) ). This means you take the product of ( y ) and 3, and then subtract that value from 5. The final result is ( 5 - 3y ).
5 - 3y
y² - y - 6 = (y + 2)(y - 3)
No.
If y = 2x+3 then the y intercept at is 3 on the y axis but if y = 2x-3 then the y intercept is at -3 on the y axis
The expression for 5 minus the product of ( y ) and 3 can be written as ( 5 - (3y) ). This means you take the product of ( y ) and 3, and then subtract that value from 5. The final result is ( 5 - 3y ).
5 - 3y
y = -35
y² - y - 6 = (y + 2)(y - 3)
y - 3
y(y-3)(y+3)
No.
If you multiplied all the terms by y2, you could simplify this to -3y3.
4(y - 3)(y + 3)
If y = 2x+3 then the y intercept at is 3 on the y axis but if y = 2x-3 then the y intercept is at -3 on the y axis
You have to put your heart into it!
y^3 + y^2 - 6 (y+2) (y-3) i think