5 - 3y
y² - y - 6 = (y + 2)(y - 3)
No.
If y = 2x+3 then the y intercept at is 3 on the y axis but if y = 2x-3 then the y intercept is at -3 on the y axis
You have to put your heart into it!
5 - 3y
y = -35
y² - y - 6 = (y + 2)(y - 3)
y - 3
y(y-3)(y+3)
No.
If you multiplied all the terms by y2, you could simplify this to -3y3.
4(y - 3)(y + 3)
If y = 2x+3 then the y intercept at is 3 on the y axis but if y = 2x-3 then the y intercept is at -3 on the y axis
You have to put your heart into it!
y^3 + y^2 - 6 (y+2) (y-3) i think
The one(s) where the y coordinate is:five times the x coordinate plus three;five times the x coordinate minus three;three plus five times the x coordinate; orthree minus five times the x coordinatedepending upon which of the following equations is intended (as there are missing operators in the question):y = 5x + 3y = 5x - 3y - 5x = 3y + 5x = 3[Note equations 1 & 3 are the same equation written in different forms.]