97 is one example.
The first number greater than 106637 where the thousands and units digits are the same is 106640. In this number, the thousands digit is 6 and the units digit is also 0, satisfying the condition. The next possible candidates would be 106641, 106642, and so on, but they do not meet the requirement of having matching thousands and units digits. Thus, 106640 is the answer.
The two digit numbers in which the tens digit is five greater than the units digit are:5061728394The number we are looking for is ten times the sum of its digits, and so must be a multiple of 10. The only one of the above numbers which fits this is 50, as 5 is five greater than 0, and 50 = 10 x (5+0).
The last two digits (the tens and units) are divisible by 4.This is equivalent to the following two conditions:If the tens digit is even, the units digit must be 0, 4 or 8If the tens digit is odd, the units digit must be 2 or 6For divisibility by 9, calculate the digital root: this is the sum of all the digits in the number. Repeat with the digits of this number - and keep repeating until you are down to a single digit. It that is 9, then the number is divisible by 9 and if not, it is not.
Let the two-digit number be represented as (10t + u), where (t) is the tens digit and (u) is the units digit. Given the conditions, we have the equations (t + u = 12) and (u - t = 2). Solving these, we find (u = 7) and (t = 5). Thus, the two-digit number is 57.
The number 999,999,999 has 9 digits. Each digit represents a place value from the billions down to the units, and in this case, all the digits are 9s.
What is the units digit of the least whole number greater than 1000 whose digits are all different?
The first number greater than 106637 where the thousands and units digits are the same is 106640. In this number, the thousands digit is 6 and the units digit is also 0, satisfying the condition. The next possible candidates would be 106641, 106642, and so on, but they do not meet the requirement of having matching thousands and units digits. Thus, 106640 is the answer.
The two digit numbers in which the tens digit is five greater than the units digit are:5061728394The number we are looking for is ten times the sum of its digits, and so must be a multiple of 10. The only one of the above numbers which fits this is 50, as 5 is five greater than 0, and 50 = 10 x (5+0).
Any two digit number in which: (a) the units digit is not 0, and (b) the two digits are different will form a new 2-digit number when the digits are interchanged.
The units digit of a two digit number exceeds twice the tens digit by 1. Find the number if the sum of its digits is 10.
17
-4
I am a three digit number. all of my digit is multiples of 2. my hundreds digit is the lowest even number. the sum of my digits is 16. the units digit is the same as the difference between my hundreds and tens digits.
The last two digits (the tens and units) are divisible by 4.This is equivalent to the following two conditions:If the tens digit is even, the units digit must be 0, 4 or 8If the tens digit is odd, the units digit must be 2 or 6For divisibility by 9, calculate the digital root: this is the sum of all the digits in the number. Repeat with the digits of this number - and keep repeating until you are down to a single digit. It that is 9, then the number is divisible by 9 and if not, it is not.
If the last two digits are divisible by 4 then the number is divisible by 4. Thus, if the tens digit is even and the units digit is 0 or 4 or 8 OR if the tens digit is odd and the units digit is 2 or 6 then the number is divisible by 4.
Let the two-digit number be represented as (10t + u), where (t) is the tens digit and (u) is the units digit. Given the conditions, we have the equations (t + u = 12) and (u - t = 2). Solving these, we find (u = 7) and (t = 5). Thus, the two-digit number is 57.
42.21 or 84.42