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In a certain two-digit number the tens' digit exceeds the units' by 5 What is the number if it is known that the number is equal to ten times the sum of the digits?
The two digit numbers in which the tens digit is five greater than the units digit are:5061728394The number we are looking for is ten times the sum of its digits, and so must be a multiple of 10. The only one of the above numbers which fits this is 50, as 5 is five greater than 0, and 50 = 10 x (5+0).
What are the rules for divisibility rules for 4 and 9?
The last two digits (the tens and units) are divisible by 4.This is equivalent to the following two conditions:If the tens digit is even, the units digit must be 0, 4 or 8If the tens digit is odd, the units digit must be 2 or 6For divisibility by 9, calculate the digital root: this is the sum of all the digits in the number. Repeat with the digits of this number - and keep repeating until you are down to a single digit. It that is 9, then the number is divisible by 9 and if not, it is not.
What is the secret number if it is greater than 25 and less than 50 and the tens digit is an odd number and the sums of the digits is less than 10?
The secret number must be a two-digit number greater than 25 and less than 50. Since the tens digit is odd, it can be 3, 5, or 7. However, the sum of the digits must be less than 10, so the only possible tens digit is 3. The units digit can be any number from 0 to 9 that, when added to 3, results in a sum less than 10. Therefore, the secret number is 31.
Find the first number greater than 106637 where its tens and units digits are the same?
it is 106,644
The sum of the digits in two- digit number is 15 If the number is 6 more than 15 times the units digit find the number?
If the sum of the digits in a two-digit number is 15, and the number is 6 more than 15 times the units digit, the number is 96. Let A and B be the digits. (A is the tens digit and B is the units digit) A + B = 15, therefore A = 15 - B 10A + B = 15B + 6Substituting for A, and solving for B...10(15 - B) + B = 15B + 6150 - 10B + B = 15B + 6150 - 9B = 15B + 6144 - 9B = 15B144 = 24BB = 6 Back substitute B into first equation and solve for A...A + 6 = 15A = 9 Therefore, the digits are 9 and 6, so the number is 96.
