There is an infinite number that can have that perimeter
Infinitely many. Select any number, L, such that 12 < L < 24. Let W = 24 - L. Then a rectangle with sides of length L cm and width W cm will have a perimeter of 48 cm. And since the choice of L was arbitrary, there are infinitely many possible values of L and thence infnitely many rectangles.
12
The edge length of a regular hexagon with a perimeter of 24 cm is 24/6 = 4 cm
3
There is an infinite number that can have that perimeter
There would be an infinite number of rectangles possible
Infinitely many. Select any number, L, such that 12 < L < 24. Let W = 24 - L. Then a rectangle with sides of length L cm and width W cm will have a perimeter of 48 cm. And since the choice of L was arbitrary, there are infinitely many possible values of L and thence infnitely many rectangles.
perimeter = 2 (b+h) = 20 there are an infinite number of rectangles that meet the requirement
12
2*(5 + 20) cm = 2*25 cm = 50 cm.
330سم
The edge length of a regular hexagon with a perimeter of 24 cm is 24/6 = 4 cm
Perimeter = 7*24 = 168 cm
the answer is 11 sq cm
3
Depends what you are drawing on.