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For starters, the number 3 is divisible by 3 but not by 2. Next, 9, 27 etc. All the odd multiples of 3 are divisible by 3 but not 2. So there is an infinite number of numbers that are divisible by 3 and not 2.
it is 2,3,6because 4152 the 2 is divisible by 2and if you add up all the numbers it = 12 and 12 is divisible by 2&3 and if a number is divisible by 2 and 3 then its divisible by 6
it is divisible by all three
Even numbers are divisible by 2. Even numbers that are divisible by 3 must be divisible by 2 and by 3, so they have to be divisible by 2 x 3.6, 12, 18, 24 …
Yes. If a number is evenly divisible by both 3 and 4, it will also be divisible by 6.This is because the prime factor of 3 is [3] -- in other words, 3 is a prime number -- and the prime factors of 4 are [2, 2].Thus, any number that is divisible by 3 and 4 will have as part of its prime factors the set [2, 2, 3]. (The smallest such number is 12, which is 2 x 2 x 3.) Since the prime factors of 6 are [2, 3] -- and [2, 3] is a subset of [2, 2, 3] -- then any such number must also be divisible by 6.Another way to look at it is to note that all numbers which are divisible by both 3 and 4 are also divisible by 12 (which is 3 x 4). Since 12 is divisible by 6, then all multiples of 12 will also be divisible by 6.
For starters, the number 3 is divisible by 3 but not by 2. Next, 9, 27 etc. All the odd multiples of 3 are divisible by 3 but not 2. So there is an infinite number of numbers that are divisible by 3 and not 2.
it is 2,3,6because 4152 the 2 is divisible by 2and if you add up all the numbers it = 12 and 12 is divisible by 2&3 and if a number is divisible by 2 and 3 then its divisible by 6
it is divisible by all three
Even numbers are divisible by 2. Even numbers that are divisible by 3 must be divisible by 2 and by 3, so they have to be divisible by 2 x 3.6, 12, 18, 24 …
Yes. If a number is evenly divisible by both 3 and 4, it will also be divisible by 6.This is because the prime factor of 3 is [3] -- in other words, 3 is a prime number -- and the prime factors of 4 are [2, 2].Thus, any number that is divisible by 3 and 4 will have as part of its prime factors the set [2, 2, 3]. (The smallest such number is 12, which is 2 x 2 x 3.) Since the prime factors of 6 are [2, 3] -- and [2, 3] is a subset of [2, 2, 3] -- then any such number must also be divisible by 6.Another way to look at it is to note that all numbers which are divisible by both 3 and 4 are also divisible by 12 (which is 3 x 4). Since 12 is divisible by 6, then all multiples of 12 will also be divisible by 6.
All numbers divisible by 9 are divisible by 3; since 9 = 3 x 3 all multiples of 9 are also multiples of 3. However, all numbers divisible by 3 are not divisible by 9, eg 6 = 2 x 3 but 6 is not divisible by 9 (since 6 is not a multiple of 9) - it only takes one counter example to disprove a theory.
Yes, 324 is divisible by 3. A number is divisible by 3 if the sum of its digits is divisible by 3. In this case, 3 + 2 + 4 = 9, which is divisible by 3. Therefore, 324 is divisible by 3.
Well, darling, the positive integers divisible by 2 are all the even numbers, and the ones divisible by 3 are those multiples of 3. So, to find the numbers divisible by either 2 or 3, you just need to combine these two sets. In other words, it's the set of all even numbers and multiples of 3. Voilà!
416 is divisible by 2 but is not divisible by 3.
Last digit (0) is even, so it is divisible by 2 4 + 3 + 2 + 0 = 9 which is divisible by 3, so it is divisible by 3 last digit is 0 or 5, so it is divisible by 5 4 + 3 + 2 + 0 = 9 which is divisible by 9, so it is divisible by 9 last digit is 0, so it is divisible by 10 → 4320 is divisible by all the numbers 2, 3, 5, 9, 10
Yes, it is divisible by 2 because it ends with 2, it is also divisible bye 3 because 1+3+2=6. 6 is divisible by 3, therefor 132 is divisible by 3.
Answer - How do you tell if a number is divisible by 3?you add all the digits in the number and see if that number can be divided by 3 Answer - A whole number is divisible by 3 if the sum of its digits is divisible by what?Three (3) Examples:* 27 -- 2+7=9 * 13452 -- 1+3+4+5+2=15 -- 1+5=6If the sum of the digits is divisible by 3, the number is also divisible by 3. Or just do the division.