The derivative of logx, assuming base 10, is 1/(xln10).
It is 1/(x*ln 10)
y=logx y=10 logx= 10 10logx = 10log1 logx = log1 x = 1 //NajN
A dot A = A2 do a derivative of both sides derivative (A) dot A + A dot derivative(A) =0 2(derivative (A) dot A)=0 (derivative (A) dot A)=0 A * derivative (A) * cos (theta) =0 => theta =90 A and derivative (A) are perpendicular
The derivative of e7x is e7 or 7e.The derivative of e7x is 7e7xThe derivative of e7x is e7xln(7)
the derivative is 0. the derivative of a constant is always 0.
Derivative of 4x is 4.
X(logX-1) + C
*First off if we assume this log to be base 10 next we can use the product rule (d/dx (3)*logx+d/dx(logx)*3) 1.derivative of a constant is zero so that gives us 0*logx as our first term (simplifies to zero) next we have to differentiate logx that gives us 3*(1/xln(10)) so that leaves 0logx+3*(1/xln(10)) simplify...... 3/xln(10)
logx^3logx^2log14 is 3logx2logxlog14 this equals 6 log14 (logx)^2 So for example, if y=6log14(logx)^2 the log x = square root of (y/6(log14))
logx^2=2 2logx=2 logx=1 10^1=x x=10
y=logx y=10 logx= 10 10logx = 10log1 logx = log1 x = 1 //NajN
log(100x) can be written as log100 + logx. This =2+logx
-logx=21.1 logx=-21.1 e^-21.1=x
logx = 2 so x = 10logx = 102 = 100 ie x = 100.
log3 + logx=4 log(3x)=4 3x=10^4 x=10,000/3
You can't solve this since it isn't an equation.There is also an ambiguity (it's hard to write math on a typewriter keyboard) - are we talking about log(x3) or maybe logx(3)?Restate the question: Simplify log(x3)Answer: 3log(x)You could explain this by saying: log(x3) = log[(x)(x)(x)] = logx + logx + logx = 3logx. The general rule is log(xn) = nlogx.
log base 10 x = logx
logx = 0.25 =1/4 4logx = 1 log x^4 = 1 x^4 = 10 x = 4th root of 10 =1.778