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How long is the diagonal of the box whose length width and height are 30cm 24cmand 18cm respectively?
Wiki User
∙ 15y ago
the equation is L^2= w^2 + h^2 + l^2 where L= length of diagonal, w=width, h=height, and l= length,
L= sqrt( (30)^2 + (24)^2 + (18)^2)= (approx) 42.2 cm
Wiki User
∙ 15y ago
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If the diagonal measurement is 15 inches what is the length and height of a rectangle?
The answer can not be calucalted without additional information. If you only know the diagnol measurement, there are an infinite number of possible lengths for the adjoining sides. If this is a question regarding the sizing of TV screens, there are two current formats: standard, where the length to height ratio is 4:3; and letterbox (or widescreen) where the length to height ration is 16:9. Using these ratios and the diagnol length, you can calculate the length and height measurements by establishing: Length = 1.3333 * Height Then: (Diagonal)^2 = (Height)^2 + (1.3333 * Height)^2
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How do you compute the diagonal of a cube?
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How long is the diagonal of the box whose length width and height are 50cm 50cm and 50cm respectively?
The long diagonal will be sqrt(7500) cm = 86.60 cm (to 2 dp)
How do you count the number of squares crossed by the diagonal in a rectangle?
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Find the height and length of a tv set if the diagonal of the tv is 26 inches and the length is 14 inches more than the height?
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If a box has a height of 56 inches what would the length of the diagonal be?
Since the length and breadth are not given, the length of the diagonal can be anything from the smallest fraction to the largest number of units.
What is the area of a rectangle with a diagonal length of 17 centimeters and height of length 8 centimeters?
Diagonal = 17 cm and height = 8 cm so Length = sqrt[172 - 82] = sqrt(225) = 15 cm Then area = length*height = 15*8 = 120 cm2
How do you find the length of a rectangular diognal?
The length of the diagonal (not diognal), is sqrt(Length^2 + Breadth^2 + Height^2).
How do you find the height of a rectangular box when length is 7 m and width is 5 m and diagonal length 10m?
I guess the diagonal length given is from one corner of the box to the opposite corner reached by traversing one length side, one edge side and one height side. Using Pythagoras, the length of the diagonal of the base (length by width) can be found. Using this diagonal and the height of the box, the diagonal from corner-to-opposite-corner of the box can be found using Pythagoras. However, as this [longer] diagonal is know, the height can be found by rearranging this last use of Pythagoras: Diagonal_base2 = length2 + width2 Diagonal_box2 = diagonal_base2 + height2 ⇒ height = √(diagonal_box2 - diagonal_base2 ) = √(diagonal_box2 - (length2 + width2)) = √(diagonal_box2 - length2 - width2) Now that the formula has been derived, plugging in (substituting) the various lengths will allow the height to be calculated.
What is the length breadth height in the room?
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If the diagonal measurement is 15 inches what is the length and height of a rectangle?
The answer can not be calucalted without additional information. If you only know the diagnol measurement, there are an infinite number of possible lengths for the adjoining sides. If this is a question regarding the sizing of TV screens, there are two current formats: standard, where the length to height ratio is 4:3; and letterbox (or widescreen) where the length to height ration is 16:9. Using these ratios and the diagnol length, you can calculate the length and height measurements by establishing: Length = 1.3333 * Height Then: (Diagonal)^2 = (Height)^2 + (1.3333 * Height)^2
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If d is the diagonal and h is the height Let, l=length of rectangle we have By pythagrous theorem d square= l square + h square therefore l square= d square - h square
What is the length of one diagonal if the base a measure 16 and the base b is 24 and has the area of 40 and a ratio of 2 is to 3?
If it's a rectangle and you know its length and height then use Pythagoras' theorem to find the length of its diagonal
If the length of a rectangular television screen is 20 inches and height is 15 inches what is the length of its diagonal in inches?
(202 + 152)0.5 = 25"
