the equation is L^2= w^2 + h^2 + l^2 where L= length of diagonal, w=width, h=height, and l= length,
L= sqrt( (30)^2 + (24)^2 + (18)^2)= (approx) 42.2 cm
The answer can not be calucalted without additional information. If you only know the diagnol measurement, there are an infinite number of possible lengths for the adjoining sides. If this is a question regarding the sizing of TV screens, there are two current formats: standard, where the length to height ratio is 4:3; and letterbox (or widescreen) where the length to height ration is 16:9. Using these ratios and the diagnol length, you can calculate the length and height measurements by establishing: Length = 1.3333 * Height Then: (Diagonal)^2 = (Height)^2 + (1.3333 * Height)^2
The length of the other diagonal works out as 12cm
The diagonal is 3.61cm
The edge length of a cube with a diagonal of 9 ft is: 5.196 feet.
The diagonal is 20.
The long diagonal will be sqrt(7500) cm = 86.60 cm (to 2 dp)
To find the length of a diagonal in a rectangle, use the Pythagorean method. Diagonal length = square root(length squared + height squared).
Length- Height-
Since the length and breadth are not given, the length of the diagonal can be anything from the smallest fraction to the largest number of units.
Diagonal = 17 cm and height = 8 cm so Length = sqrt[172 - 82] = sqrt(225) = 15 cm Then area = length*height = 15*8 = 120 cm2
The length of the diagonal (not diognal), is sqrt(Length^2 + Breadth^2 + Height^2).
I guess the diagonal length given is from one corner of the box to the opposite corner reached by traversing one length side, one edge side and one height side. Using Pythagoras, the length of the diagonal of the base (length by width) can be found. Using this diagonal and the height of the box, the diagonal from corner-to-opposite-corner of the box can be found using Pythagoras. However, as this [longer] diagonal is know, the height can be found by rearranging this last use of Pythagoras: Diagonal_base2 = length2 + width2 Diagonal_box2 = diagonal_base2 + height2 ⇒ height = √(diagonal_box2 - diagonal_base2 ) = √(diagonal_box2 - (length2 + width2)) = √(diagonal_box2 - length2 - width2) Now that the formula has been derived, plugging in (substituting) the various lengths will allow the height to be calculated.
5m,4m,3m respectively
If d is the diagonal and h is the height Let, l=length of rectangle we have By pythagrous theorem d square= l square + h square therefore l square= d square - h square
The answer can not be calucalted without additional information. If you only know the diagnol measurement, there are an infinite number of possible lengths for the adjoining sides. If this is a question regarding the sizing of TV screens, there are two current formats: standard, where the length to height ratio is 4:3; and letterbox (or widescreen) where the length to height ration is 16:9. Using these ratios and the diagnol length, you can calculate the length and height measurements by establishing: Length = 1.3333 * Height Then: (Diagonal)^2 = (Height)^2 + (1.3333 * Height)^2
If it's a rectangle and you know its length and height then use Pythagoras' theorem to find the length of its diagonal
(202 + 152)0.5 = 25"