First, we need to determine the slope of the given line represented by the equation (4x + y + 7 = 0). Rearranging this, we find the slope is (-4). A line that is perpendicular to this will have a slope of (\frac{1}{4}). Using the point-slope form with the point ((-4, -3)), the equation of the line in slope-intercept form is (y + 3 = \frac{1}{4}(x + 4)), which simplifies to (y = \frac{1}{4}x - 2).
If you mean 7 = 7x-3 then the perpendicular slope is -1/7 and the equation is y = -1/7x
Perpendicular slope: -1/4 Perpendicular equation: y-0 = -1/4(x-3) => y = -0.25x+3
2-3
Without an equality sign and not knowing the plus or minus values of y and 7 it can't be considered to be a straight line equation therefore finding its perpendicular equation is impossible.
Perpendicular slope: 1/2 Perpnedicular equation: y-5 = 1/2(x-2) => y = 0.5x+4
If you mean 7 = 7x-3 then the perpendicular slope is -1/7 and the equation is y = -1/7x
That depends on the equation that it is perpendicular too which has not been given but both equations will meet each other at right angles.
Perpendicular slope: -1/4 Perpendicular equation: y-0 = -1/4(x-3) => y = -0.25x+3
2-3
General formula
Without an equality sign and not knowing the plus or minus values of y and 7 it can't be considered to be a straight line equation therefore finding its perpendicular equation is impossible.
That would depend on its slope which has not been given.
If you mean y = 3x+8 then the perpendicular slope will be -1/3 and the equation works out as 3y = -x+9
Perpendicular slope: 1/2 Perpnedicular equation: y-5 = 1/2(x-2) => y = 0.5x+4
Perpendicular slope: -2/5 Perpendicular equation: y--4 = -2/5(x-3) => 5y--20 = -2x-3 => 5y = -2x-14 Perpendicular equation in its general form: 2x+5y+14 = 0
A line that is perpendicular to the segment of a plane and passes through the midpoint.
As for example the perpendicular equation to line y = 2x+6 could be y = -1/2x+6 because the negative reciprocal of 2x is -1/2x