T(n) = 12 - n2
It is: 25-7n
7n - 3
The sequence 3, 7, 11, 15 is an arithmetic sequence where each term increases by 4. The first term (a) is 3, and the common difference (d) is 4. The nth term can be expressed using the formula: ( a_n = a + (n - 1)d ). Substituting the values, the nth term is ( a_n = 3 + (n - 1) \cdot 4 = 4n - 1 ).
Un = 25 - 7n
The nth term is 7n-3 and so the next term will be 39
11
1...2....3....43...7...11..157 - 3 = 411 - 7 = 415 - 11 = 4(the start of the nth term is 4n)4 x 1 = 4(but the first term is 3, so...)4 -1 = 3nth term = 4n - 1
It is: 25-7n
7n - 3
Un = 25 - 7n
The nth term is 7n-3 and so the next term will be 39
To find the nth term of the sequence -4, -1, 4, 11, 20, 31, we first identify the pattern in the differences between the terms: 3, 5, 7, 9, 11, which increases by 2 each time. This suggests a quadratic relationship. The nth term can be expressed as ( a_n = n^2 + n - 4 ). Thus, the nth term of the sequence is ( a_n = n^2 + n - 4 ).
To find the nth term of the sequence -4, -1, 4, 11, 20, 31, we first determine the differences between consecutive terms: 3, 5, 7, 9, 11. The second differences are constant at 2, indicating a quadratic relationship. The nth term can be expressed as ( a_n = n^2 + n - 4 ). Thus, the nth term is ( a_n = n^2 + n - 4 ).
1 +3 =4 +3+4 =11 +3+4+4 =22 +3+4+4+4 37 +3+4+4+4+4 .... u can c where i am goin here
To find the nth term formula for the sequence -4, -1, 4, 11, 20, 31, we first observe the differences between consecutive terms: 3, 5, 7, 9, 11, which are increasing by 2. This indicates a quadratic relationship. The nth term formula can be derived as ( a_n = n^2 + n - 4 ).
The sequence 3, 7, 11 is an arithmetic sequence where the first term is 3 and the common difference is 4. The nth term formula for an arithmetic sequence can be expressed as ( a_n = a_1 + (n - 1)d ), where ( a_1 ) is the first term and ( d ) is the common difference. Substituting the values, the nth term formula for this sequence is ( a_n = 3 + (n - 1) \cdot 4 ), which simplifies to ( a_n = 4n - 1 ).
The nth term is: 3n-7 and so the next number will be 11