T(n) = 12 - n2
7n - 3
It is: 25-7n
Un = 25 - 7n
The nth term is 7n-3 and so the next term will be 39
To find the nth term of the sequence -4, -1, 4, 11, 20, 31, we first identify the pattern in the differences between the terms: 3, 5, 7, 9, 11, which increases by 2 each time. This suggests a quadratic relationship. The nth term can be expressed as ( a_n = n^2 + n - 4 ). Thus, the nth term of the sequence is ( a_n = n^2 + n - 4 ).
11
1...2....3....43...7...11..157 - 3 = 411 - 7 = 415 - 11 = 4(the start of the nth term is 4n)4 x 1 = 4(but the first term is 3, so...)4 -1 = 3nth term = 4n - 1
It is: 25-7n
7n - 3
Un = 25 - 7n
The nth term is 7n-3 and so the next term will be 39
To find the nth term of the sequence -4, -1, 4, 11, 20, 31, we first identify the pattern in the differences between the terms: 3, 5, 7, 9, 11, which increases by 2 each time. This suggests a quadratic relationship. The nth term can be expressed as ( a_n = n^2 + n - 4 ). Thus, the nth term of the sequence is ( a_n = n^2 + n - 4 ).
1 +3 =4 +3+4 =11 +3+4+4 =22 +3+4+4+4 37 +3+4+4+4+4 .... u can c where i am goin here
The sequence 3, 7, 11 is an arithmetic sequence where the first term is 3 and the common difference is 4. The nth term formula for an arithmetic sequence can be expressed as ( a_n = a_1 + (n - 1)d ), where ( a_1 ) is the first term and ( d ) is the common difference. Substituting the values, the nth term formula for this sequence is ( a_n = 3 + (n - 1) \cdot 4 ), which simplifies to ( a_n = 4n - 1 ).
The nth term is: 3n-7 and so the next number will be 11
The nth term is: 3n-7 and so the next number will be 11
2n+5