If: 11x-8y = 32 Then: -8y = -11x+32 And: y = 1.375x-4 in slope-intercept form
5x+8y = 40 8y = -5x+40 y = -5/8x+5 in slope intercept form
First find the slope of the given line . 5x + 8y =17 Put this into the 'y = mx + c '. form. Hence 8y = -5x + 17 y =(-5/8)x +17/8 '-5/8' is the slope of the given line. To find the perpendicular slope use the equation mm' = -1 Hence substituting (-5/8)m' = -1 m' = (-1)(-8/5) (Note the inversion of the numbers) m' = 8/5 (Note the double negative multiplies out to a positive), = 1 3/5 = 1.6 is the slope of the perpendicular line.
It can be simplified to: x-5y
It is: x-5y simplified
6x+8y = 12 8y = -6x+12 Divide all terms by 8:- y = -0.75x+1.5 which is now in slope intercept form
Need to put in function form. Y =mX + c 6X + 8Y = 12 8Y = - 6X + 12 Y = - 3/4X + 3/2 ----------------------- read off function m = - 3/4 ---------------------slope
Without an equality sign the given expression can't be considered to be a straight line equation.
2y = 6x - 8y = 3x - 4========m(slope) = 3=========
The slope m' of a line perpendicular to a line with slope m is such that m'm = -1 → m' = -1/m A line with slope m' through point (X, Y) has equation: y - Y = m'(x - X) → The line perpendicular to 7x - 8y = 12 through p (-3, 1) is found: 7x - 8y = 12 → 8y = 7x - 12 → y = (7/8)x - 3/2 → The slope of 7x - 8y = 12 is m = 7/8 → The slope of the perpendicular line is m' = -1/m = -1/(7/8) = -8/7 → The line through P with this slope m' is: y - 1 = -8/7(x - -3) → y = (-8/7)x - 24/7 + 1 → y = (-8/7)x - 17/7 This can be rearranged into: y = (-8/7)x - 17/7 → 7y = -8x - 17 → 7y + 8x + 17 = 0
14
The answer depends on what the feasible region is and on what operator is between 6x and 8y.
0.25
6x-3y
Yes because the slope or gradient are the same 4/3
If: 11x-8y = 32 Then: -8y = -11x+32 And: y = 1.375x-4 in slope-intercept form
5x+8y = 40 8y = -5x+40 y = -5/8x+5 in slope intercept form