There is not enough information to answer the question.
The altitude forms a right angle triangle with half the side length and one side as the hypotenuse. Using Pythagoras: (½side)² + altitude² = side² → altitude² = side² - ¼side² → altitude² = ¾side² → altitude = (√3)/2 × side → altitude = (√3)/2 × 6 = 3√3 ≈ 5.2
Side=x, Altitude= a (x/2)2+(x/2)2= Sqrt(a)2
The sides are 2*sqrt(3) units in length.
Using Pythagoras: 62+32 = 45 and the square root of this is the altitude
Given an altitude of 12 units, an equilateral triangle has side lengths of 13.9 (13.85641) units.
No. The altitude is smaller.
The triangle's altitude is 8.7 (8.66025) cm.
Each side of the triangle is 16.16581 units in length.
The altitude of an equilateral triangle is (√3)/2*a. where 'a' is the side of the triangle. It can be just find by giving a perpendicular to the base of the triangle, the base of the triangle become a/2 and one side is a. so by applying Pythagoras theorem we will get the desired formula.
There is not enough information to answer the question.
Given side lengths of 8 units, an equilateral triangle will have an altitude of 7 (6.9282) units.
With an altitude of 10 units, this triangle's sides each measure 11.55 (11.54701) units.
The length of each side is 9.2376 cm. (rounded)
The altitude forms a right angle triangle with half the side length and one side as the hypotenuse. Using Pythagoras: (½side)² + altitude² = side² → altitude² = side² - ¼side² → altitude² = ¾side² → altitude = (√3)/2 × side → altitude = (√3)/2 × 6 = 3√3 ≈ 5.2
Side=x, Altitude= a (x/2)2+(x/2)2= Sqrt(a)2
The sides are 2*sqrt(3) units in length.