2x2 + 7x + 3 = (2x + 1)(x + 3)If 2x2 + 7x + 3 = 0 then:(2x + 1)(x + 3) = 0⇒ (2x + 1) = 0 → x = -1/2or (x + 3) = 0 → x = - 3
(2x + 1)(x + 3)
x2 + 7x = 2x2 + 6 x2 - 2x2 + 7x = 6 -x2 +7x - 6 = 0 or alternatively x2 - 7x + 6 = 0
It is: 2x2-7x+6 = (2x-3)(x-2) when factored
You would factor 2x2 + 7x + 6 into (2x + 3) (x+2)
2x2 + 7x + 3 = (2x + 1)(x + 3)If 2x2 + 7x + 3 = 0 then:(2x + 1)(x + 3) = 0⇒ (2x + 1) = 0 → x = -1/2or (x + 3) = 0 → x = - 3
2x2-7x+3 = 0 (2x-1)(x-3) = 0 x = 1/2 or x = 3
x2+7x=-2x2+6 3x2+7x-6=0 (3x-2)(x+3)=0 3x-2=0 or x+3=0 x=2/3 or x=-3
2x2 + 7x - 15 = (2x - 3)(x + 5)
(2x + 1)(x + 3)
x2 + 7x = 2x2 + 6 x2 - 2x2 + 7x = 6 -x2 +7x - 6 = 0 or alternatively x2 - 7x + 6 = 0
-6
The factorisation is as follows: 2x2 + 7x - 9 = (x - 1)(2x + 9).
2x2 + 7x + 6 = 2x2 + 4x + 3x + 6 = 2x(x + 2) + 3(x + 2) = (x + 2)(2x + 3)
It is: 2x2-7x+6 = (2x-3)(x-2) when factored
2x2 + 7x - 15 = 02x2 + 10x - 3x - 15 = 0(2x2 - 3x) + (10x - 15) = 0x(2x - 3) + 5(2x - 3) = 0(2x - 3)(x + 5) = 0(2x - 3) = 0 or (x + 5) = 0x = 3/2 or x = -5
If you mean: 2x2+7x+5 then it is (2x+5)(x+1) when factored