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(x^2-2) (x^2+3x+5)= x^2(x^2+3x+5) -2(x^2+3x+5)= x^4 +3x^3 +5x^2 -2x^2 -6x -10= x^4 +3x^3 +3x^2 -6x -10
2(3x + 4) = 6x + 8 3(x - 5) = 3x - 15 6x + 8 - 3x + 15 = 3x + 23
2(3x + 4) = 6x + 8 3(x - 5) = 3x - 15 6x + 8 - 3x + 15 = 3x + 23
5x - 5 = 3x - 9 add 5 to both sides: 5x =3x -4 subtract 3x from both sides: 2x = -4 Divide both sides by 2: x = -2
If: y = 3x+4 and y = 2-7x Then: 3x+4 = 2-7x So: 3x+7x = 2-4 => 10x = -2 => x = -1/5 By substitution: y = 17/5 Solution: x = -1/5 and y = 17/5
(x^2-2) (x^2+3x+5)= x^2(x^2+3x+5) -2(x^2+3x+5)= x^4 +3x^3 +5x^2 -2x^2 -6x -10= x^4 +3x^3 +3x^2 -6x -10
2(3x + 4) = 6x + 8 3(x - 5) = 3x - 15 6x + 8 - 3x + 15 = 3x + 23
The equivalent expression of 3x-9 plus 3x plus 5 is negative 4.
2(3x + 4) = 6x + 8 3(x - 5) = 3x - 15 6x + 8 - 3x + 15 = 3x + 23
2(3x + 4) = 6x + 8 3(x - 5) = 3x - 15 6x + 8 - 3x + 15 = 3x + 23
If the question is x + 4z - 5 - 3x when x = 2 and z = 3x, then First simplify the original statement x + 4z - 5 - 3x = 4z - 5 - 2x Secondly substitute in 3x for z 4z - 5 - 2x = 4*3x - 5 - 2x = 12x - 5 - 2x = 10x - 5 Lastly substitute 2 for the x 10x - 5 = 10*2 - 5 = 20 - 5 = 15 or x + 4z - 5 - 3x when x = 2 and z = 3x, so z = 3*2 = 6 x + 4z - 5 - 3x = 4z - 5 - 2x (replace the variables with the corresponding values) = 4*6 - 5 - 2*2 = 24 - 5 - 4 = 24 - 9 = 15
2(3x + 4) = 6x + 8 3(x - 5) = 3x - 15 6x + 8 - 3x + 15 = 3x + 23
3x - 5 = 9 3x = 9 + 5 3x = 14 x = 14/3 or 4 2/3
2(3x + 4) = 6x + 8 3(x - 5) = 3x - 15 6x + 8 - 3x + 15 = 3x + 23
5x - 5 = 3x - 9 add 5 to both sides: 5x =3x -4 subtract 3x from both sides: 2x = -4 Divide both sides by 2: x = -2
3x * (x - 4) = 3x*x - 3x*4 = 3x^2 - 12x.
If: y = 3x+4 and y = 2-7x Then: 3x+4 = 2-7x So: 3x+7x = 2-4 => 10x = -2 => x = -1/5 By substitution: y = 17/5 Solution: x = -1/5 and y = 17/5