(3x)^(2-4) = (3x)^-2 = (9x2)^-1 = 1/(9x2)
(3x - 1)(3x + 19)
9x2 + 3x / 3x equals (3x + 1).9x2 + 3x divided by x is 9x + 3 , and then divided by 3 yields the 3x +1.
(-3x - 1)(3x - 7)
(3x - y)(3x - y) - 81
If you mean: 9x2+3x-2 = (3x+2)(3x-1) when factored
9x2 + 12x + 4 = 9x2 + 6x + 6x + 4 = 3x(3x + 2) + 2(3x + 2) = (3x + 2)(3x + 2) = (3x + 2)2
(3x)^(2-4) = (3x)^-2 = (9x2)^-1 = 1/(9x2)
9x2 + 9x - 10 =(3x - 2)(3x + 5)
(3x-4)(3x+4)
There's a chance this was notated incorrectly. It looks like it wants to be some combination of 3x and 2. 9x2 + 12x + 4 = (3x + 2)(3x + 2) or (3x + 2)2 -9x2 - 12x - 4 = -(3x + 2)2 9x2 - 12x + 4 = (3x - 2)2 -9x2 + 12x - 4 = -(3x - 2)2
9x2 + 6x + 1 = 9x2 + 3x + 3x + 1 = 3x(3x + 1) + 1(3x + 1) = (3x + 1)(3x + 1) or (3x +1)2
3x(x^2 - 3x + 1)
(3x + y)(3x - y)
(3x + 4)(3x - 4)
(3x - 1)(3x + 19)
9x2 + 3x / 3x equals (3x + 1).9x2 + 3x divided by x is 9x + 3 , and then divided by 3 yields the 3x +1.