(3x-4)(3x+4)
If the question could more exactly be phrased as, "What is the value of x when 9x2 - 16 = 0", the answer is, x = 4 or -4. This answer can be found by factoring 9x2 - 16 into (3x + 4)(3x - 4) and setting each factor equal to zero.
Factor: 9x2 - 25.
If you mean: 9x2+3x-2 = (3x+2)(3x-1) when factored
9x2 + 9x - 10 =(3x - 2)(3x + 5)
9x2+2x-7 = (9x-7)(x+1) when factored
(3x + 4)(3x - 4)
If the question could more exactly be phrased as, "What is the value of x when 9x2 - 16 = 0", the answer is, x = 4 or -4. This answer can be found by factoring 9x2 - 16 into (3x + 4)(3x - 4) and setting each factor equal to zero.
If you mean: 9x2-36x+16 then it is not a perfect square because its discriminant is greater than zero
16? using 16, you have (3x2 + 4)(3x2 + 4) = 9x2 + 24x + 16
so 9x2 = -16. Doesnt work without going to imaginary numbers, x2 = -16/9 ie x = 4i/3
The expression (0x) typically indicates a hexadecimal number starting with the prefix "0x," which signifies that the number following it is in base 16. However, if "0x" is interpreted literally as it stands, it represents the value 0 in hexadecimal, which is equivalent to 0 in decimal as well. Therefore, (0x) equals 0.
If im not mistaken, it should be 2.
Presumably you mean: 9x2+24x+16? (3x+4)(3x+4)
0x-34 = -34
Factor: 9x2 - 25.
-1
The property used to rewrite 9x2 + 9x3 is the Distributive Property. Using the Distributive Property the expression can be rewritten as 9x2 + 9x2 + 9x2 or 27x2.