If the question could more exactly be phrased as, "What is the value of x when 9x2 - 16 = 0", the answer is, x = 4 or -4. This answer can be found by factoring 9x2 - 16 into (3x + 4)(3x - 4) and setting each factor equal to zero.
Factor: 9x2 - 25.
If you mean: 9x2+3x-2 = (3x+2)(3x-1) when factored
9x2 + 9x - 10 =(3x - 2)(3x + 5)
9x2+2x-7 = (9x-7)(x+1) when factored
(3x + 4)(3x - 4)
If the question could more exactly be phrased as, "What is the value of x when 9x2 - 16 = 0", the answer is, x = 4 or -4. This answer can be found by factoring 9x2 - 16 into (3x + 4)(3x - 4) and setting each factor equal to zero.
If you mean: 9x2-36x+16 then it is not a perfect square because its discriminant is greater than zero
16? using 16, you have (3x2 + 4)(3x2 + 4) = 9x2 + 24x + 16
so 9x2 = -16. Doesnt work without going to imaginary numbers, x2 = -16/9 ie x = 4i/3
If im not mistaken, it should be 2.
Presumably you mean: 9x2+24x+16? (3x+4)(3x+4)
0x-34 = -34
-1
Factor: 9x2 - 25.
The property used to rewrite 9x2 + 9x3 is the Distributive Property. Using the Distributive Property the expression can be rewritten as 9x2 + 9x2 + 9x2 or 27x2.
12x^3+17x^2+5x=0x(12x^2+17x+5)=0x(x+1)(12x+5)=0x=0x=-1x=-5/12