-8x -7y
3y + 18 = -8x + 3Subtract 18 from each side:3y = -8x - 15Divide each side by 3:y = (-8/3)x - 5
(1, 1)
To find the constant in the expression (8x + 3y - 2x + 6 - 4), first simplify it. Combine like terms: (8x - 2x = 6x) and (3y) remains as is. The constant terms are (6 - 4), which equals (2). Therefore, the constant in the expression is (2).
7x+3y=-52 3(8x-y=-74) 7x+3y=-52 24x-3y=-222 7x=-52 + 24x=-222 31x=-274 x=8.8387
8x + 3y = 248x - 8x + 3y = -8x + 243y = - 8x + 243y/3 = (- 8x + 24)/3y = -8x/3 + 24/3y = (-8/3)x + 8 this is the slope-intercept form of the equation of the line, y = mx + b, where the slope m is -8/3 and the y-intercept b is 8.
4x + 3y = 8x + y so 3y - y = 8x - 4x ie 2y = 4x so y = 2x
-8x+3y=12 3y = 8x+12 y = (8/3)x + 4 So it will be a line with slope 8/3 and y intercept of 4
-8x -7y
3y + 18 = -8x + 3Subtract 18 from each side:3y = -8x - 15Divide each side by 3:y = (-8/3)x - 5
(1, 1)
16x2 + 8x + 1 - 9y2 = (4x + 1)2 - (3y)2 which is a difference of two squares. = (4x + 1 + 3y)*(4x + 1 - 3y)
To find the constant in the expression (8x + 3y - 2x + 6 - 4), first simplify it. Combine like terms: (8x - 2x = 6x) and (3y) remains as is. The constant terms are (6 - 4), which equals (2). Therefore, the constant in the expression is (2).
7x+3y=-52 3(8x-y=-74) 7x+3y=-52 24x-3y=-222 7x=-52 + 24x=-222 31x=-274 x=8.8387
10x - 5y + 2x - 3y = 12x - 8y
35
The answer would be Y=8/3x + 5/-3 This is how to do it: First, you have to isolate 'Y' in the equation. You do this by adding the opposite of all terms, not 'Y' though, to both sides of the equation (but first you have to make sure ALL like terms are added(none here), and you have to tik-tok(convert all subtraction to adding negatives instead(Example x-3 --->x+ -3)(none here)) : 8x - 3y - 5=0 ----> 8x + -3y + -5=0 ---> (8x + -8x) + -3y + (-5 + 5) = 0+ -8x + 5 ---> -3y= 0+ -8x + 5 Now you divide all terms by the coefficient of y, here being -3. DON'T FORGET IF IT'S POSITIVE OR NEGATIVE!!!!!! Like here: -3y/-3 = -8x/-3 + 5/-3 -----> Y= 8/3 x + 5/-3 Hope I helped :-)