distance from point (0,0) to 3+2i is |3+2i| =sqrt(9+4)=sqrt(13)
so the radius of the circle is sqrt(13) and its area is sqrt(13)*sqrt(13)*Pi = 13*Pi = 40.84
1.75 + 1.75i7i/2 + 2i = 3.5i + 2i = 5.5i
The four roots are:1 + 2i, 1 - 2i, 3i and -3i.
In the reaction (2H^+ + SO_4^{2-} + Ca^{2+} + 2I^- \rightarrow CaSO_4 + 2H^+ + 2I^-), the spectator ions are those that do not change during the reaction. Here, the ( H^+ ) ions and ( I^- ) ions are present on both sides of the equation and do not participate in the formation of the precipitate ( CaSO_4 ). Therefore, the spectator ions are ( H^+ ) and ( I^- ).
-5-7=-126i-8i=-2i-12-2i is your final answer
8.2462 (rounded)
10 + 6i and 7 + 2i = 10 + 6i + 7 + 2i = 17 + 8i
1.75 + 1.75i7i/2 + 2i = 3.5i + 2i = 5.5i
It is 3 minus 2i
The four roots are:1 + 2i, 1 - 2i, 3i and -3i.
In the reaction (2H^+ + SO_4^{2-} + Ca^{2+} + 2I^- \rightarrow CaSO_4 + 2H^+ + 2I^-), the spectator ions are those that do not change during the reaction. Here, the ( H^+ ) ions and ( I^- ) ions are present on both sides of the equation and do not participate in the formation of the precipitate ( CaSO_4 ). Therefore, the spectator ions are ( H^+ ) and ( I^- ).
(-2 + 3i) + (-1 - 2i) = -2 + 3i - 1 - 2i = -2 - 1 + 3i - 2i = -3 + i
-5-7=-126i-8i=-2i-12-2i is your final answer
2H+ + SO42- + Ca2+ + 2I- CaSO4 + 2H+ + 2I-
Not necessarily, take for example the equation x^2=5-12i. Then, 3-2i satisfies the equation. However, 3+2i does not because (3+2i)^2 = 5+12i.
2i + 3cl2 --> 2icl3
8.2462 (rounded)
x2 + 5x + not really sure what that extra plus is for... this is the most you can factor it... x(x + 5)