Q: Find the area of a rhombus with diagonals of 8 cm and 7 cm?

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54

the diagonals of a rhombus measure 16 cm and 30 cm.find its perimeter.

That will depend on the length of the other diagonal because area of a rhombus is 0.5*product of its diagonals.

Its area is base times perpendicular height or 0.5 times the product of its diagonals

Find the area of a rhombus whose side is 6 cm and whose altitude is 4 cm? . Area = base * height Altitude = height. Altitude = 4 cm . A rhombus has all 4 sides equal, so the base = 6 cm . Area = base * height . Area = ____sq. cm.

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54

The area is 56 cm2

Answer63cm2. False

The lengths of the diagonals work out as 12 cm and 16 cm

14*8 = 112 sq cm

the diagonals of a rhombus measure 16 cm and 30 cm.find its perimeter.

If those are the diagonals of the rhombus then its area: 0.5*14*8 = 112 square cm

That will depend on the length of the other diagonal because area of a rhombus is 0.5*product of its diagonals.

always

Double the area and find 2 numbers that have a sum of 42.5 and a product of 375 which will work out as 30 and 12.5 by using the quadratic equation formula. Therefore the diagonals are of lengths 30 and 12.5 which will intersect each other half way at right angles forming 4 right angle triangles inside the rhombus with sides of 15 cm and 6.25 cm Using Pythagoras' theorem each out side length of the rhombus is 16.25 cm and so 4 times 16.25 = 65 cm which is the perimeter of the rhombus.

Its area is base times perpendicular height or 0.5 times the product of its diagonals

Area of the rhombus: 0.5*7.5*10 = 37.5 square cm Perimeter using Pythagoras: 4*square root of (3.75^2 plus 5^2) = 25 cm