A square with a side length of 4cm has an area of 16cm2
a≈2.83cm The sides are the square root of 8 cm, approximately 2.8284 cm
The diagonal length of a square with a 900 square foot area is: 42.43 feet.
If you take the square of the long side and add it to the square of the short side, you get the diagonal (hypotenuse) squared. Then just find square root of that. For example, if short side is 3cm and long side is 4cm: 9 + 16 = 25, so the diagonal would be the square root of 25 ie. 5.
Each side is 2cm
if you mean 4cm by 4cm square, then the area is 16cm2
A square with a side length of 4cm has an area of 16cm2
Yes (apart from units):If the side of a square is 4cm then itsperimeter is 4cm + 4cm + 4cm + 4cm = 4 x 4cm = 16cm;area is 4cm x 4cm = 16cm2
a≈2.83cm The sides are the square root of 8 cm, approximately 2.8284 cm
The diagonal length of a square with a 900 square foot area is: 42.43 feet.
The area of square is : 100.0
The square's diagonal is 11.314 cm
If you take the square of the long side and add it to the square of the short side, you get the diagonal (hypotenuse) squared. Then just find square root of that. For example, if short side is 3cm and long side is 4cm: 9 + 16 = 25, so the diagonal would be the square root of 25 ie. 5.
Each side is 2cm
The area is 72 cm2
As no shape has been given for the area it is impossible to given the length of the diagonal - the diagonal can be ANY length greater than 0 (assuming you can define what diagonal means for the shape). If you are referring to a square with an area of 11 square inches then: Using Pythagoras: diagonal² = side² + side² = 2 × side² → side² = diagonal² ÷ 2 area = side² = diagonal² ÷ 2 → diagonal² = 2 × area → diagonal = √(2 × area) = √(2 × 11 sq in) = √22 in ≈ 4.69 in If you mean an 11 inch square, ie a square with 11 inches along each side: Use Pythagoras: Diagonal² = √(2 × sidelength²) → diagonal = side_length × √2 → diagonal = 11 in × √2 ≈ 15.6 in
Its diagonal is 1 unit.