It is: 0.5*4*4 = 8 square cm
The answer depends on what information you do have: the length of a side, or a diagonal, the area, ... If a side is of length s cm then the perimeter is 4*s cm.
Its other diagonal works out as 32 cm using Pythagoras' theorem It will have 4 right angle triangles of 20 cm by 16 cm by 12 cm Its area is: 0.5*32*24 = 384 square cm Its area is also: 0.5*16*12*4 = 384 square cm
The area of square is : 16.0
A square with a side length of 2 cm has an area of 4 square cm.
It is: 0.5*4*4 = 8 square cm
The answer depends on what information you do have: the length of a side, or a diagonal, the area, ... If a side is of length s cm then the perimeter is 4*s cm.
Its other diagonal works out as 32 cm using Pythagoras' theorem It will have 4 right angle triangles of 20 cm by 16 cm by 12 cm Its area is: 0.5*32*24 = 384 square cm Its area is also: 0.5*16*12*4 = 384 square cm
Each square has an area of 1 cm square, for 4 squares altogether area is 4 cm square. Or we can say we have a big square 2cm by 2cm, whose area is 4 cm square.
The area of square is : 16.0
A square with a side length of 2 cm has an area of 4 square cm.
Area = 64 cm2 so length of side = 8cm Then, by Pythagoras, length of diagonal = sqrt[82 + 82] = 8*sqrt(2) = 11.3137 cm (to 4 dp)
The area of a square is length times width. Therefore, based on your question: 4 cm x 4 cm = 16 sq cm. So the area of your square is 16 square centimetres.
Area = 9 cm * 4 cm = 36 square cm
area is the product of sides; 4 x 4 = 16 square cm
area of square = side ^2 side = sqrt(4) = 2 cm
If that means (2 times 4) then the area of the square is 8*8 = 64 square cm