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What is the area of an equilateral triangle with a side of 6 inches?
15.588 square inches.
What is the length of an altitude of an equilateral triangle with a side length of 9 inches?
Use Pythagoras' theorem: 92-4.52 = 60.75 and the square root of this is the altitude which is 7.794 inches to 3 d.p.
If one side of the hexagon is 6 inches what is the area?
Assuming that the hexagon is regular (all sides are the same), it can be comprised of 6 equilateral triangles of side length 6 (in this case). Area of a equilateral triangle is: (side length^2*√3)/4 Each triangle is of area: 62.353829072479572 inches square. 62.353829072479572*6 = 374.12297443487743 inches square approx.
How do you work out the area of an equilateral triangle with a perpendicular height of XV inches showing details of your work and giving your final answer to an appropriate degree of accuracy?
Height in inches = XV=15 Area of a triangle = base length times perpendicular height divided by 2 An equilateral triangle has three equal sides with three equal interior angles of 60o An equilateral triangle can be considered as being two right angled triangles joined together. So we can make use of trigonometry to find the base length: opposite/tangent = adjacent length of the right angled triangle 15/tangent 60o = 8.660254038 inches Base length of the equilateral triangle = 8.660254038*2 = 17.32050808 inches Area = 17.32050808*15/2 = 129.9038106 square inches Therefore the area of the equilateral triangle is 130 square inches which is correct to three significant figures. Answered by David Gambell, Merseyside, England.
What is the area of an equilateral triangle with sides 10 inches and height of 7 inches?
Area of the equilateral triangle: 0.5*10*10*sin(60 degrees) = 25 times square root of 3 which is about 43.301 square inches to 3 decimal places. If it is an equilateral triangle with 3 equal sides of 10 inches then its height would be about 8.66 inches and not 7 inches
When a square is divided by diagonal is it called an equilateral triangle?
no but the diagonal divides the square into two equilateral triangles. An equilateral triangle is a triangle that has two sides of the same length
What is the area of an equilateral triangle with a side of 6 inches?
15.588 square inches.
What is the length of an altitude of an equilateral triangle with a side length of 9 inches?
Use Pythagoras' theorem: 92-4.52 = 60.75 and the square root of this is the altitude which is 7.794 inches to 3 d.p.
If one side of the hexagon is 6 inches what is the area?
Assuming that the hexagon is regular (all sides are the same), it can be comprised of 6 equilateral triangles of side length 6 (in this case). Area of a equilateral triangle is: (side length^2*√3)/4 Each triangle is of area: 62.353829072479572 inches square. 62.353829072479572*6 = 374.12297443487743 inches square approx.
How do you work out the area of an equilateral triangle with a perpendicular height of XV inches showing details of your work and giving your final answer to an appropriate degree of accuracy?
Height in inches = XV=15 Area of a triangle = base length times perpendicular height divided by 2 An equilateral triangle has three equal sides with three equal interior angles of 60o An equilateral triangle can be considered as being two right angled triangles joined together. So we can make use of trigonometry to find the base length: opposite/tangent = adjacent length of the right angled triangle 15/tangent 60o = 8.660254038 inches Base length of the equilateral triangle = 8.660254038*2 = 17.32050808 inches Area = 17.32050808*15/2 = 129.9038106 square inches Therefore the area of the equilateral triangle is 130 square inches which is correct to three significant figures. Answered by David Gambell, Merseyside, England.
What is the area of an equilateral triangle with sides 8 inches long?
27.713 square inches.
A parallelogram that is not a square with all sides the same length?
an equilateral triangle;)
What is the area of an equilateral triangle with side of 10 inches and height of 7 inches?
Area of the equilateral triangle: 0.5*10*10*sin(60 degrees) = 25 Times Square root of 3 which is about 43.301 square inches to 3 decimal places. If it is an equilateral triangle with 3 equal sides of 10 inches then its height would be about 8.66 inches and not 7 inches
What is the area of an equilateral triangle with sides 10 inches and height of 7 inches?
Area of the equilateral triangle: 0.5*10*10*sin(60 degrees) = 25 times square root of 3 which is about 43.301 square inches to 3 decimal places. If it is an equilateral triangle with 3 equal sides of 10 inches then its height would be about 8.66 inches and not 7 inches
What is the area of an equilateral triangle with a height of 9 inches?
Its area is 46.8 (46.76533) square inches.
What is the area rounded to the nearest tenth of a square inch of an equilateral triangle that has a perimeter of 24 inches?
Area of equilateral triangle: 0.5*8*8*sin(60 degrees) = 27.7 square inches rounded
Surface area of an equilateral triangle?
0.4330 times the length of a side (in square units of length)
