0
That will be a vertical line that passes through the parabola at the point where it's slope is equal to zero.
The first step then, is to take the derivative of the curve with respect to x:
y = x2 + 2x + 6
dy/dx = 2x + 2
Then let dy/dx equal zero, and solve for x:
0 = 2x + 2
2x = -2
x = -1
So the axis of symmetry is the line x = -1.
What else can I help you with?
What is the axis of symmetry for the function - y equals x squared plus 2x plus 1?
y=x2+2x+1 -b -2 2a= 2= -1 = axis of symmetry is negative one.
What is the equation of the axis of symmetry plus x2-3?
-1
What is the line of symmetry of the graph y equals -x2 plus 2x-2?
the line of symmetry would occur at x=0
What is the axis of symmetry for y-x2 2x-4?
To find the axis of symmetry for the quadratic equation ( y = -x^2 + 2x - 4 ), you can use the formula ( x = -\frac{b}{2a} ), where ( a ) and ( b ) are the coefficients from the equation in standard form ( y = ax^2 + bx + c ). Here, ( a = -1 ) and ( b = 2 ). Plugging in the values, the axis of symmetry is ( x = -\frac{2}{2 \times -1} = 1 ). Thus, the axis of symmetry is ( x = 1 ).
What is the factorization of this trinomial -x2 plus 2x plus 48?
-x2 + 2x + 48 = (x +6)(8 - x)
What is the axis of symmetry of x2 plus 2x-3?
It is at: (-1, 0)
What is the axis of symmetry for the function - y equals x squared plus 2x plus 1?
y=x2+2x+1 -b -2 2a= 2= -1 = axis of symmetry is negative one.
What is the equation of the axis of symmetry plus x2-3?
-1
What is the vertex and the axis of symmetry for the function y equals x2 plus 4x plus 1?
Take the derivative: y' = 2x + 4. Set equal to zero: 2x + 4 = 0 --> x = -2. Substitute into original and y = -3. Axis of symmetry is x = -2. Vertex is (-2,-3)
What is the line of symmetry of the graph y equals -x2 plus 2x-2?
the line of symmetry would occur at x=0
Y equals x2 plus 2x plus 1?
y = x2 + 2x + 1zeros are:0 = x2 + 2x + 10 = (x + 1)(x + 1)0 = (x + 1)2x = -1So that the graph of the function y = x + 2x + 1 touches the x-axis at x = -1.
What is an equation of the axis of symmetry of the parabola represented by y equals -x2 plus 6x-4?
Line of symmetry: x = 3
What is the axis of symmetry for y-x2 2x-4?
To find the axis of symmetry for the quadratic equation ( y = -x^2 + 2x - 4 ), you can use the formula ( x = -\frac{b}{2a} ), where ( a ) and ( b ) are the coefficients from the equation in standard form ( y = ax^2 + bx + c ). Here, ( a = -1 ) and ( b = 2 ). Plugging in the values, the axis of symmetry is ( x = -\frac{2}{2 \times -1} = 1 ). Thus, the axis of symmetry is ( x = 1 ).
An equation of the axis of symmetry of the graph y equals -x2 plus 8x-7?
y = x2 + 8x - 7 a = 1, b = 8, c = -7 the equation of the axis of symmetry: x = -b/2a x = -8/(2*1) = -4
What is the factorization of this trinomial -x2 plus 2x plus 48?
-x2 + 2x + 48 = (x +6)(8 - x)
X2 plus 2x plus -6 equals 0?
x2 + 2x -6 = 0 x2 + 2x + 1 = 7 (x + 1)2 = 7 x = -1 ± √7
What is the factorization of the trinomial below -x2 plus 2x plus 48?
-x2 + 2x + 48 = (-x - 6)(x - 8)
