3.14159265358979323846264338327950288419716939937510
That is correct.
Digits after (to the right of) the decimal point contribute to the accuracy of the number, not its magnitude (or size). So only the digits to the left of the decimal point contribute to the magnitude. Digits after (to the right of) the decimal point contribute to the accuracy of the number, not its magnitude (or size). So only the digits to the left of the decimal point contribute to the magnitude. Digits after (to the right of) the decimal point contribute to the accuracy of the number, not its magnitude (or size). So only the digits to the left of the decimal point contribute to the magnitude. Digits after (to the right of) the decimal point contribute to the accuracy of the number, not its magnitude (or size). So only the digits to the left of the decimal point contribute to the magnitude.
You must add 9 digits (or 12 digits, depending on the country) after the decimal point, and eliminate the decimal point. Thus (assuming the "short scale") you get: 53,620,000,000.You must add 9 digits (or 12 digits, depending on the country) after the decimal point, and eliminate the decimal point. Thus (assuming the "short scale") you get: 53,620,000,000.You must add 9 digits (or 12 digits, depending on the country) after the decimal point, and eliminate the decimal point. Thus (assuming the "short scale") you get: 53,620,000,000.You must add 9 digits (or 12 digits, depending on the country) after the decimal point, and eliminate the decimal point. Thus (assuming the "short scale") you get: 53,620,000,000.
One way is to multiply the numbers ignoring the decimal point. If the first multiplicand has d1 digits after the decimal point, and the second has d2 digits after the decimal point, then their product has (d1 + d2) digits after the decimal point.An alternative for the second stage is to estimate the answer to determine where the decimal point should go.
If the two decimal numbers have x and y digits after the decimal points, then the product has (x + y) digits after the decimal point.
That is correct.
When writing a decimal out in words, the numbers before the decimal are written as if they are whole numbers, and the numbers after the decimal are read as digits. Therefore, for example, 150.35 is read one hundred and fifty point three five.
Digits after (to the right of) the decimal point contribute to the accuracy of the number, not its magnitude (or size). So only the digits to the left of the decimal point contribute to the magnitude. Digits after (to the right of) the decimal point contribute to the accuracy of the number, not its magnitude (or size). So only the digits to the left of the decimal point contribute to the magnitude. Digits after (to the right of) the decimal point contribute to the accuracy of the number, not its magnitude (or size). So only the digits to the left of the decimal point contribute to the magnitude. Digits after (to the right of) the decimal point contribute to the accuracy of the number, not its magnitude (or size). So only the digits to the left of the decimal point contribute to the magnitude.
You must add 9 digits (or 12 digits, depending on the country) after the decimal point, and eliminate the decimal point. Thus (assuming the "short scale") you get: 53,620,000,000.You must add 9 digits (or 12 digits, depending on the country) after the decimal point, and eliminate the decimal point. Thus (assuming the "short scale") you get: 53,620,000,000.You must add 9 digits (or 12 digits, depending on the country) after the decimal point, and eliminate the decimal point. Thus (assuming the "short scale") you get: 53,620,000,000.You must add 9 digits (or 12 digits, depending on the country) after the decimal point, and eliminate the decimal point. Thus (assuming the "short scale") you get: 53,620,000,000.
The digits from 0 to 9, and the decimal point (or comma, depending on the country).The digits from 0 to 9, and the decimal point (or comma, depending on the country).The digits from 0 to 9, and the decimal point (or comma, depending on the country).The digits from 0 to 9, and the decimal point (or comma, depending on the country).
One way is to multiply the numbers ignoring the decimal point. If the first multiplicand has d1 digits after the decimal point, and the second has d2 digits after the decimal point, then their product has (d1 + d2) digits after the decimal point.An alternative for the second stage is to estimate the answer to determine where the decimal point should go.
If two decimal numbers have x and y digits after the decimal point respectively, then their product has (x + y) digits after the decimal point.
If the two decimal numbers have x and y digits after the decimal points, then the product has (x + y) digits after the decimal point.
.625 is a terminating decimal. A decimal is considered terminating if it has a finite number of digits after the decimal point. In the case of .625, there are only three digits after the decimal point, making it a terminating decimal.
Yes, it can.
If it ever ends, then it is.If there are no digits after the decimal point, it's an integer.
The number 0.03 has two significant digits, which are the digits "3" and "0" after the decimal point. However, in terms of total digits, it has three digits: the "0" before the decimal, the "0" after the decimal, and the "3."